ghattasak
Member level 1
- Joined
- Dec 31, 2012
- Messages
- 33
- Helped
- 0
- Reputation
- 0
- Reaction score
- 0
- Trophy points
- 1,286
- Activity points
- 1,595
having an array of 32*32 when using num2str i get a char array of 32*94 why? i cannot use bin2dec on it
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups = num2str(m');
the array groups will be of type char 32*94
i cannot convert it to decimal :S
- - - Updated - - -
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups = (m');
power2=[1,32];
for i=1:32
power2(i)=2^(i-1);
end
power2=uint32(power2);
decnum=[1,32];
for i=1:32
decnum(i)=(sum(power2.*groups(i,
));
end
decnum=uint32(decnum);
this is the updated code but it is somekind of slow if i want to do it on 500 000number
any suggestions plz?
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups = num2str(m');
the array groups will be of type char 32*94
i cannot convert it to decimal :S
- - - Updated - - -
data = uint32(randi(2^31,[32,1]));
m = de2bi((data),32);
groups = (m');
power2=[1,32];
for i=1:32
power2(i)=2^(i-1);
end
power2=uint32(power2);
decnum=[1,32];
for i=1:32
decnum(i)=(sum(power2.*groups(i,
));end
decnum=uint32(decnum);
this is the updated code but it is somekind of slow if i want to do it on 500 000number
any suggestions plz?
