The Z transform is the discrete counterpart to Laplace transform .
Is there Laplace Transform to periodic signals ? Since as well as Laplace transform the Z transform has a ROC region of convergence. So as Laplace transfor has basic transformation to cos (wt) u(t) or sin(wt) u(t) the Z transform has transformation to cos(nt) u or sin(nt) u.
The Z transform is the discrete counterpart to Laplace transform .
Is there Laplace Transform to periodic signals ? Since as well as Laplace transform the Z transform has a ROC region of convergence. So as Laplace transfor has basic transformation to cos (wt) u(t) or sin(wt) u(t) the Z transform has transformation to cos(nt) u or sin(nt) u.
I can't see a way of being more clear, probably if I improve my english... as it takes time, what I basicaly mean is that there are Z transform for the functions cos(nt) u or sin(nt) u, and probably, but not sure, there are ROC problems for the Z transform of cos(nt) or sin(nt). Thats why the query about Laplace transform of periodic signals.
i want to know whether ztransform exists for periodic discrete signal or not. u[n]sin[Ωn] is not a periodic signal . pls tell me whether it can exist for periodic
As I quoted before, there might be some problem with the ROC of the Z transform of cos(Ωn) or sin(Ωn). It is just a suspicion, there should be a ROC problem in the interval minus infinite to zero. I try to help giving this opinion, but unfortunately, I am not sure. I wish I had the ready answer.
If I were desperate to know this answer, I would write cos(Ωn) in complex form and compute the z transfor in the above interval, later I would verify if it either diverge or not. As I am lazy to perform this computation I would rather stay with my suspicion and wait to know the answer in case of someone else perform the computation.