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UC3906 battery charger for 12V 30A

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dimas_lilik

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Dear edaboarder,
I have any question about UC3906.
Can this IC use for charger 12V 30A?
I have sample schematic but after i made this schematic output only 1- 2 A
any suggestion?
 

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Hi tpetar, I know this data sheets. Did you have schematic for UC3906 for Battery Charger 12V with output current 30A?
 

Yes.If and only if the cct.is upgrade by changing the pnp,npn transistor at pin16 diode and the resistor look at the cct

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And the transformer also upgrade
 

Hi tpetar, I know this data sheets. Did you have schematic for UC3906 for Battery Charger 12V with output current 30A?

I dont have circuit with this IC sorry, datasheet point to capabilities of mentioned part. With additional power parts in circuit such as MOSfets I think this can be achieved.

;-)
 

Yes.If and only if the cct.is upgrade by changing the pnp,npn transistor at pin16 diode and the resistor look at the cct

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And the transformer also upgrade
Hi kyrietec, I try to changing the PNP and NPN transistor but output only 3 -5A. For transformer 50 A. Did you have schematic or sample circuit?
 

What is the voltage reading at this point (20V) in the actual circuit, while charging.
3731055900_1369911149.jpg
 

What you need is it circuit that can control charging , when voltage reach certain level it will stop

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What you need is it circuit that can control charging , when voltage reach certain level it will stop
 

So that's the problem. This voltage is not sufficient for this cicuit. There are many points where voltage is dropped before reaching the battery terminals. There is sense resistor, pass transistor and a rectifier diode, all dropping voltages. I think you are using 12V, not 15V transformer as shown in schematics.
AC voltage, when recified to DC by full bridge diodes and filtered by capacitor, DC increases 1,4 times AC. 15 x 1.4 = 21V DC. Why you are not getting that voltages at least at no charging state.
Frankly your cicuit is no good for use at that current. If it is dropping 5-6V at 30A, you have to dissipate 150-200 watts as heat.
 

So that's the problem. This voltage is not sufficient for this cicuit. There are many points where voltage is dropped before reaching the battery terminals. There is sense resistor, pass transistor and a rectifier diode, all dropping voltages. I think you are using 12V, not 15V transformer as shown in schematics.
AC voltage, when recified to DC by full bridge diodes and filtered by capacitor, DC increases 1,4 times AC. 15 x 1.4 = 21V DC. Why you are not getting that voltages at least at no charging state.
Frankly your cicuit is no good for use at that current. If it is dropping 5-6V at 30A, you have to dissipate 150-200 watts as heat.
Yes i use 12V. If I use 15V,I was afraid my battery quickly broken.

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What you need is it circuit that can control charging , when voltage reach certain level it will stop

- - - Updated - - -

What you need is it circuit that can control charging , when voltage reach certain level it will stop
Yes, I need control charging, when current reach certain level it will stop.
Not voltage reach, but current.
 

Hi Kyrietec, in your circuit, what are you using? Current or voltage sensor?

Circuit 1.Reset the voltage through variable resistor.If the system reset at 13.8v when the battery reach 13.8v the relay will switch on by switching off your transformer input,when the battery voltage drops the relay will switch off the start charging. Circuit 2.Connect relay the same way in cct 1.Retset the voltage through variable resistor.Inverting input is regulated voltage 5.6v,noninverting input is unregulated voltage the input depend on battery voltage .when noninverting input voltage is >or=inverting input the relay will switch on.if battery drops the relay will switch off.Both cct. switching on relay depend on voltage you reset it .Your charging current depend on your transformer.
 

Circuit 1.Reset the voltage through variable resistor.If the system reset at 13.8v when the battery reach 13.8v the relay will switch on by switching off your transformer input,when the battery voltage drops the relay will switch off the start charging. Circuit 2.Connect relay the same way in cct 1.Retset the voltage through variable resistor.Inverting input is regulated voltage 5.6v,noninverting input is unregulated voltage the input depend on battery voltage .when noninverting input voltage is >or=inverting input the relay will switch on.if battery drops the relay will switch off.Both cct. switching on relay depend on voltage you reset it .Your charging current depend on your transformer.
Many thanks for your explanation.
But i need charging with current controller. Your circuit can be use, but can not detect the battery is good or faulty?
 

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