transistor Dc analysis

[JUBAYER]

i need to calculate the voltage at the collector,base and emitter....β=100
please someone help me to find them with a little details and soon.....

the diagram is given below:

https://obrazki.elektroda.pl/4242597700_1353407529.png

 

[AMS012]

Voltage across EB is 0.65V (PNP). I through 10k across EB is 65mA. Writing the KCL at node E gives (9-Ve)/10k =65mA + (β+1) Ib. At B gives 65mA + Ib = (Vb - Vc)/10k. At C gives (Vb-Vc)/10k + β Ib = Vc/10k. And one more equation (9-Ve)/10k = Vc/10k and Ve -0.65 =Vb. Solving these equations will get you the answers.

 

[keith1200rs]

If you recognise it as a Vbe multiplier, ignoring the base current Vcb = Vbe = 0.65V. Different ratios of the base-emitter and base-collector resistors is used to give different multipliers. E.g. 10k from base to emitter and 20k from base to collector will give Vcb = 2xVbe.

Keith.