Junior Member level 2
Suppose if i take an npn transistor and apply some voltage at the base the transistor will be ON and the emitter is grounded and the output at the collector is 0V. Similarly if i make the base cutoff the emitter is open circuited and the current is 0, the collector output is supply voltage. Now my doubt is when you say open circuited does not mean the physical connection from the emitter to ground is completely gone? In that case the emitter pin should be floating? The voltage at the collector is not supply voltage?