Holy cow. This is a question techs. might ask in 101 electronics.
The diode never reaches reverse breakdown voltage and acts a simple passive +ve clamp circuit.
In the diode clamp driven by a series RC + signal 0 to 3.3V you expect the diode to have two states, ON & OFF with a series resistance you can estimate for each using the datasheet. The resistance can be estimated by V/I for forward and reverse biased from the datasheet, which I expect you can read and interpolate for 3.3V.
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What do you estimate for the diode Rs with a fixed voltage drop of (3.3-0.8)/ 100 ohms=
I being the diode current?
All TV's take the AC coupled video signal and then clamp the "back porch" after negative sync tip using an active pulse to short circuit the load for 100 ns when the output is expected to be 0V. This serves as the video 0% IRE or "black" level reference. This is an
active clamp as opposed to the passive diode clamp using a low C[pF] FET with say <1 Ohm.
Since video signals use 75 Ohm impedance and using 5 T decay times for a low steady-state (SS) error ...
Can you estimate the resistance of the switch in the ON state? R=T/C and choose C such that the output does not decay more than 1% during the Hsync period of video of 15 ms with an estimate leakage current in the OFF state of say 1uA?
Can you think of a DC coupled circuit that has a negative non-inverting level shifter function? (using a transistor with a negative Vss load)
Can you think of a way to shift the load so the negative output is no 0V and the load is now +ve so your circuit runs off a single +ve supply? is it floating?