Hello, a single LC cell was made to test delay.the phase increases linearly.how do i find the delay my square wave will get from this slope?
my slope is 1.8 degrees for each 1Mhz.
Thanks.
Yes in group delay each sine component of the pulse is delayed according
to its frequency, the delay in radians. So you know the fundamental freq,
its period, is 2 * pi radians, and its harmonics as well.
From the prior ref post :
Delta t can be calced from freg and phase shift in radians.
Hello Dana , so my LC has 38Mhz bandwidth. Suppose i want to enter a pulse with rise/fall time of 100ns.
Which means the BW of the pulse is 3.5Mhz.
I have simulated the pulse below and i got a delay of 5ns.
Given this example
How do i calculate this 5ns delay from the group delay of group-delay=1.8degree/1MHz
This filter arrangement turns any repeating waveform into a sine (or sine-like). It presents a certain impedance for any given frequency. The resulting impedance is the sum of L impedance and C impedance. And somehow we can contribute the effect of R1 which has its ohm value.
The result across R1 is attenuated amplitude. The percentage of attenuation is related to the sine (or cosine) of incoming amplitude. Or it could be initial sine-shaped component of incoming waveform.
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Hmmm... I'm finding the above is merely a rough idea of the theory.
Near resonance the delay is 90 degrees yet there's no attenuation .
At 3 or 4 times resonant freq the delay reaches maximum attenuation and 180 degree delay.
Hello Dana,regarding your assistance:
1.At 3.5MHz its -6.25.How it helps us get the pulse delay?
2.Actually its only an example.My pulse source is 74ABT04 which produses the pulse and the load is ucc5304.
How do you reccomend the source and load of the delay line given these data sheets.
Hello Dana , my pulse has rise time/fall time is 100ns
Ton=700ns and period is 2u.
In simple 50% duty cycle its f=1/period.But here is a more complex case.
How did you find its fundamental?
Thanks.