Ok, but why in output will be 16V if the transformes make 12V ?
And if an accumulator has 12V voltage, how i should count value for resistor when i want to connect buzzer for 12v ? Which voltage ?
Ok, but why in output will be 16V if the transformes make 12V ?
And if an accumulator has 12V voltage, how i should count value for resistor when i want to connect buzzer for 12v ? Which voltage ?
How to change 16V from transformator to 12V?
LED diodes? The diodes won't burn ?
Dear kokosz and etmabreu as you know Vrms = 12 v , however on the full bridge we have Vp= 1.414 Vrms - 2*.7(bridge diode voltage) = 16-1.4=14.4vQuote Originally Posted by kokosz View Post
Ok, but why in output will be 16V if the transformes make 12V ?
And if an accumulator has 12V voltage, how i should count value for resistor when i want to connect buzzer for 12v ? Which voltage ?
Because, when talking about a transform, 12V means the rms (root mean square) voltage (Vrms), and after rectification you will approach peak voltage (Vp). These are related by:
Vp = 1.414 Vrms
If you have a 12V accumulator and a 12V buzzer just connect the buzzer to the accumulator, there is no need for resistor.
You should series LED by a 1k ohm resistor and parallel to your buzzer.I want to connect buzzer and 1 red LED parallel to 12V
I want to connect buzzer and 1 red LED parallel to 12V
Hello, i have problem with my transformer 230V/12V 20W max.
I want to reinforce buzzer 12V 5mA.
Can I make rectifier brigde with 4x rectifier diode 1000V 3A ?
Now back to the buzzer. I want to reinforce it with current from transformer. How to count value of resistor when the tension of transformer has 12V and buzzer is for 12V too and 5mA (0,005A). Can I conect resistor 0,25 W?
I know that is R = ( Ucc - Ub ) / I (Ucc - tension of transformer , Ub - tesnsion of buzzer) , but R = 0V (12V - 12V) / 0,005A. Here is a mistake.
Please can anybody help me? I can' t find this problem on the net.
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