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Sizing of PMOS driver of LDO in "CADENCE"

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kishore680

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I am designing LDO with PMOS as pass transistor , It should support current upto 50mA. SO width of PMOS should be very very high. But in cadence maximum width i can give is 100u. :cry: i need ratio of 6m/1u W/L. How to do that in cadence?
 

If you need something like say 6mm of Wtotal, name your PMOS instance like NAME<59:0> with the maximum W that the technology permits (100um).
That will give you the 6mm, because you end up in your netlist with 60 PMOS devices of W=100u and L=1u.

I do not Know what technology you are using, but why are you using such a big L?
Lower your L, which makes you need a smaller W/L ratio and therefore a smaller layout.
 
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Thank you i am using UMC180 . If i use L as 180nm even then W should be quite high . BEcause to drive 50mA keeping Vds=0.2. I need very very high W/L.
 

Yes, if you want such a low dropout it will cost you quite big layout area (bigger W/L).
Nevertheless, I think you do not need to have such a high value for L.
So, if you reduce your L value, in order to maintain the same W/L relation (to have the low VDS drop that you want) you lower you W.
This way you achieve less layout area ;)
You just need to check if your leakage is small enough (due to the smaller L) to be discarded when the PowerMOS is open!
 

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