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I do not know what you want to measure.
If the opamp is Cmos and the load resistance is high then the output voltage swing is rail-to-rail.
if the opamp uses ordinary transistors then the output voltage swing depends on how many emitter-followers there are at the output.
Do you want to simulate its maximum output voltage swing?The opamp is CMOS.
Do you want to simulate its maximum output voltage swing?
Then set its voltage gain to whatever you want, feed it a suitable input sinewave and turn up the level until the output begins to clip. That is its maximum output voltage swing.
Yes. Then if the circuit is like all the other Cmos opamps its output swing will be from 0V to the positive supply voltage.For example I use an inverting configuration with a gain of 10. In the inverting input I put an AC signal. Then I change the value of voltage of this signal and I measure in the output the value when this signal start clipping.
Am I correct ?
Yes. Then if the circuit is like all the other Cmos opamps its output swing will be from 0V to the positive supply voltage.
Both the positive and negative swings do not reach the supply voltages like most Cmos opamps.the simulation I obtained is in the attachment. Do you know why I have more swing in the negative than in the positive ?