CAMALEAO
Full Member level 4
Hi everyone. I was reading this:
https://www.allaboutcircuits.com/textbook/semiconductors/chpt-8/differentiator-integrator-circuits/
and came across with this:
"However, if we apply a constant, positive voltage to the input, the op-amp output will fall negative at a linear rate, in an attempt to produce the changing voltage across the capacitor necessary to maintain the current established by the voltage difference across the resistor."
Can't understand why a positive voltage to the input will make the output go negative and the current bit on the explanation. Has anyone analysed the integrator from this point of view? Can anyone explain in another word?
Another thing that can't understand is why, in the expression, we have -Vin/(RC). Why it is negative? If we use nodal analysis this is not held.
Thanks.
https://www.allaboutcircuits.com/textbook/semiconductors/chpt-8/differentiator-integrator-circuits/
and came across with this:
"However, if we apply a constant, positive voltage to the input, the op-amp output will fall negative at a linear rate, in an attempt to produce the changing voltage across the capacitor necessary to maintain the current established by the voltage difference across the resistor."
Can't understand why a positive voltage to the input will make the output go negative and the current bit on the explanation. Has anyone analysed the integrator from this point of view? Can anyone explain in another word?
Another thing that can't understand is why, in the expression, we have -Vin/(RC). Why it is negative? If we use nodal analysis this is not held.
Thanks.