Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Multidimensional array of registers with initialization

Status
Not open for further replies.

Nuclear_Carlson

Newbie level 4
Newbie level 4
Joined
Nov 18, 2010
Messages
6
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Visit site
Activity points
1,309
I have some Verilog module with multidimensional outputs (to 7-segment LED panels of my DE1-SoC). I want to make the outputs registered. To test it, I give some dummy code to one of LED digits. Its RTL simulation passes OK, it's even compiled by Quartus, but actually it does not work.

Code:
module Top
(
    input            CLK50,
    output reg[6:0] HEX[5:0]
);

genvar i;
generate
	for(i = 0; i < 6; i++)
	begin: test
		initial
		//always@(posedge CLK50)
		begin
			HEX[i][6:0] = 7'b101_0101;
		end
	end
endgenerate

endmodule

Alas, my Quartus synthesizer gives sais me the following warning:
Code:
Warning (10855): Verilog HDL warning at Top.v(20): initial value for variable HEX should be constant
and says that that all the HEX pins are stuck on GND:
Code:
	Warning (13410): Pin "HEX[0][0]" is stuck at GND
	Warning (13410): Pin "HEX[0][1]" is stuck at GND
	Warning (13410): Pin "HEX[0][2]" is stuck at GND
	Warning (13410): Pin "HEX[0][3]" is stuck at GND
	Warning (13410): Pin "HEX[0][4]" is stuck at GND
	Warning (13410): Pin "HEX[0][5]" is stuck at GND
	Warning (13410): Pin "HEX[0][6]" is stuck at GND
	Warning (13410): Pin "HEX[1][0]" is stuck at GND
	Warning (13410): Pin "HEX[1][1]" is stuck at GND
	Warning (13410): Pin "HEX[1][2]" is stuck at GND
	Warning (13410): Pin "HEX[1][3]" is stuck at GND
	Warning (13410): Pin "HEX[1][4]" is stuck at GND
	Warning (13410): Pin "HEX[1][5]" is stuck at GND
	Warning (13410): Pin "HEX[1][6]" is stuck at GND
	Warning (13410): Pin "HEX[2][0]" is stuck at GND
	Warning (13410): Pin "HEX[2][1]" is stuck at GND
	Warning (13410): Pin "HEX[2][2]" is stuck at GND
	Warning (13410): Pin "HEX[2][3]" is stuck at GND
	Warning (13410): Pin "HEX[2][4]" is stuck at GND
	Warning (13410): Pin "HEX[2][5]" is stuck at GND
	Warning (13410): Pin "HEX[2][6]" is stuck at GND
	Warning (13410): Pin "HEX[3][0]" is stuck at GND
	Warning (13410): Pin "HEX[3][1]" is stuck at GND
	Warning (13410): Pin "HEX[3][2]" is stuck at GND
	Warning (13410): Pin "HEX[3][3]" is stuck at GND
	Warning (13410): Pin "HEX[3][4]" is stuck at GND
	Warning (13410): Pin "HEX[3][5]" is stuck at GND
	Warning (13410): Pin "HEX[3][6]" is stuck at GND
	Warning (13410): Pin "HEX[4][0]" is stuck at GND
	Warning (13410): Pin "HEX[4][1]" is stuck at GND
	Warning (13410): Pin "HEX[4][2]" is stuck at GND
	Warning (13410): Pin "HEX[4][3]" is stuck at GND
	Warning (13410): Pin "HEX[4][4]" is stuck at GND
	Warning (13410): Pin "HEX[4][5]" is stuck at GND
	Warning (13410): Pin "HEX[4][6]" is stuck at GND
	Warning (13410): Pin "HEX[5][0]" is stuck at GND
	Warning (13410): Pin "HEX[5][1]" is stuck at GND
	Warning (13410): Pin "HEX[5][2]" is stuck at GND
	Warning (13410): Pin "HEX[5][3]" is stuck at GND
	Warning (13410): Pin "HEX[5][4]" is stuck at GND
	Warning (13410): Pin "HEX[5][5]" is stuck at GND
	Warning (13410): Pin "HEX[5][6]" is stuck at GND

Ignore initial constructs is off. When I replace initial to always@(posedge CLK50), just for test, it works fine, but I want initial values in my registers.

How can I solve the problem?

- - - Updated - - -

UPD: It also sais that
Code:
Warning (10855): Verilog HDL warning at Top.v(14): initial value for variable HEX should be constant

- - - Updated - - -

UPD: It looks like *initial* statement can be synthesised, but multiple *initial* statement cannot.

Don't you know a way to use *generate-for* construction inside *initial* statement?
 

Thank you, comrade! It worked!

P.S. Cannot you also tell me the difference between the two designs?

Works:
Code:
module Top
(
    input            CLK50,
    output reg[6:0] HEX[5:0]
);

integer i;
initial begin
	for(i = 0; i < 6; i++)
	begin
		HEX[i][6:0] = 7'b101_0101;
	end
end

endmodule

Fails:
Code:
    module Top
    (
        input            CLK50,
        output reg[6:0] HEX[5:0]
    );
    
    genvar i;
    generate
    	for(i = 0; i < 6; i++)
    	begin: test
    		initial
    		begin
    			HEX[i][6:0] = 7'b101_0101;
    		end
    	end
    endgenerate
    
    endmodule
 

I believe, you'll use a regular for loop inside the initial block.

- - - Updated - - -

As you found out, multiple initial statements aren't supported. The other syntax is a straightforward way to achieve what you want, I think.
 
Unravel the for loop to see what the code looks like.

The one that works results in this:
Code:
integer i;
initial begin
  HEX[0][6:0] = 7'b101_0101;
  HEX[1][6:0] = 7'b101_0101;
  HEX[2][6:0] = 7'b101_0101;
  ...
  HEX[5][6:0] = 7'b101_0101;
end

The code that doesn't work does this:
Code:
initial begin
  HEX[0][6:0] = 7'b101_0101;
end
initial begin
  HEX[1][6:0] = 7'b101_0101;
end
initial begin
  HEX[2][6:0] = 7'b101_0101;
end
...
initial begin
  HEX[5][6:0] = 7'b101_0101;
end

Which means you are assigning an array in multiple blocks, which isn't allowed. This is similar to the problem where many new Verilog coders do something like this:
Code:
always @ (posedge reset) begin
  if (reset) begin
    my_signal <= 1'b0;
  end
end

always @ (posedge clock) begin
  if (enable) begin
    my_signal <= my_input;
  end
end
 

Excuse me, I meant — what was the difference between this

Does not synthesize
Code:
module Top
(
    input            CLK50,
    output reg[5:0][6:0] HEX
);

initial begin
	genvar i;
	generate
		for(i = 0; i < 6; i++) begin: test
			HEX[i][6:0] = 7'b101_0101;
		end
	endgenerate
end

endmodule

and that (does synthesize)
Code:
module Top
(
    input            CLK50,
    output reg[5:0][6:0] HEX
);

initial begin
	integer i;
	for(i = 0; i < 6; i++) begin
		HEX[i][6:0] = 7'b101_0101;
	end
end

endmodule
 

If you look in the LRM 12.2 states the allowed procedural statements are:
— Selection statements (see 12.4 and 12.5)
— Loop statements (see 12.7)
— Jump statements (see 12.8)
— Sequential and parallel blocks (see 9.3)
— Timing controls (see 9.4)
— Process control (see 9.5 through 9.7)
— Procedural assignments (see 10.4 through 10.9)
— Subroutine calls (see Clause 13)

As you can see generate is not included. Generate isn't a procedural statement, therefore it can't exist in an initial block.
 

In reply to the question in #2, there is no functional difference between the two code forms. It is just that the second case with the generate-for loop, the synthesis tool is not smart enough to figure out that the assignment statements will be to mutually exclusive elements of the array. The synthesis tool has a limitation that it can only figure that out if the code is within a single initial block.
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top