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[Moved]: N path filter design

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can you please send me your schematic and you pss+pac setup ?
I didn't create any schematic.
Simply I modified your netlist.
Then I ran modified netlist by Cadence Spectre.

See my netlist.
All informations are there.
 
Last edited:
I didn't create any schematic.
Simply I modified your netlist.
Then I ran modified netlist by Cadence Spectre.

See my netlist.
All informations are there.

Thank you very much for your response
I just want to know how duty cycle effect on frequency response of N path filter?
and how can I replace switch with transmission gate transistor ?I find out that I ca measure on resistance of transmission gate and play around with width and length of transistor to get on resistance which is equal to on Resistance of switch?
Thank you very much
 

I didn't create any schematic.
Simply I modified your netlist.
Then I ran modified netlist by Cadence Spectre.

See my netlist.
All informations are there.

Hi
Actually I did what t you had mentioned in the netlist ,my circuit looks that work however I do not understand that why you put vt1 and vt2 which are open and closed volatge equal to(vdd/2*(1-0.001) and vdd/2*(1-0.001)
I am wondering if you can give me concept behnid that or introduce a book or linke that I can read about it
 

I just google spectre -h relay I could not find anything which was helpful
Cn you give me a link to read about it
I really appreciate
 

Hi again
In N path filter ,in schematic I have replace ideal switch with transmission gate, and I expect to get result which is close to ideal one(using ideal switch),I simulate circuit several time but I got error every time ,
ERROR IS following:
Do you have any ideal how should I solve this problem ??
I have attached the schematic
Error found by spectre at time = 500.821 us during periodic steady state analysis `pss'.
ERROR (SPECTRE-16192): No convergence achieved with the minimum time step specified. Last acceptable solution computed at 500.002 us.

The values for those nodes that did not converge on the last Newton iteration are given below. The manner in which the convergence criteria were not satisfied is also given.
Failed test: | Value | > RelTol*Ref + AbsTol

Top 10 Solution too large Convergence failure:

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I(V5:p) = -3.28528 A, previously 115.33 uA.
        update too large:  | -4.77147 A | > 328.711 uA + 1 pA
    V(NM7_D) = 1.31374 MV, previously -3.26124 V.
        update too large:  | 876.162 kV | > 131.375 V + 1 uV
    I(V1:p) = -13.2054 GA, previously 21.2747 uA.
        update too large:  | -1.61061 GA | > 1.32054 MA + 1 pA
    V(R0_MINUS) = -127.819 MV, previously -2.19448 V.
        update too large:  | 11.3246 MV | > 12.7819 kV + 1 uV
    I(V7:p) = -2.55637 kA, previously -43.8896 uA.
        update too large:  | 226.492 A | > 255.637 mA + 1 pA
    V(PM3.n1) = -165.229 MV, previously 169.877 uV.
        update too large:  | 8.16306 MV | > 16.5229 kV + 1 uV
    V(PM3:int_d) = -165.229 MV, previously -15.4957 V.
        update too large:  | 8.16306 MV | > 16.5229 kV + 1 uV
    V(PM3:int_s) = -165.23 MV, previously -2.19435 V.
        update too large:  | 8.16306 MV | > 16.523 kV + 1 uV
    V(PM2.n1) = -166.9 MV, previously 169.714 uV.
        update too large:  | 8.21645 MV | > 16.69 kV + 1 uV
    V(PM2:int_d) = -166.901 MV, previously -18.8709 V.
        update too large:  | 8.21645 MV | > 16.6901 kV + 1 uV
 Top 10 Residue too large Convergence failure:
    V(NM7_D) = 1.31374 MV, previously -3.26124 V.
        residue too large: | -21.0591 MA | > 2.10591 kA + 1 pA
    V(PM2:int_s) = -166.901 MV, previously -2.19439 V.
        residue too large: | 360.388e+15 A | > 36.0388 TA + 1 pA
    V(PM3:int_s) = -165.23 MV, previously -2.19435 V.
        residue too large: | 364.103e+15 A | > 36.4103 TA + 1 pA
    V(PM6.n1) = 25.3748 V, previously 174.456 uV.
        residue too large: | -210.137e+15 A | > 21.0137 TA + 1 pA
    V(PM3.n1) = -165.229 MV, previously 169.877 uV.
        residue too large: | -364.103e+15 A | > 36.4103 TA + 1 pA
    V(PM2.n1) = -166.9 MV, previously 169.714 uV.
        residue too large: | -360.388e+15 A | > 36.0388 TA + 1 pA
    V(PM4q.n1) = 78.0137 V, previously 21.2585 uV.
        residue too large: | -1.13064e+18 A | > 113.064 TA + 1 pA
    V(NM2.n1) = -25.5679 V, previously 15.6785 uV.
        residue too large: | -14.7425e+18 A | > 1.47425e+15 A + 1 pA
    V(NM4.n1) = -25.5649 V, previously 16.2375 uV.
        residue too large: | -14.7283e+18 A | > 1.47283e+15 A + 1 pA
    V(NM7.n1) = -5.68213 kV, previously -2.4807 V.
        residue too large: | 4.35893e+21 A | > 435.893e+15 A + 1 pA



The following set of suggestions might help you avoid convergence difficulties.

1. Evaluate and resolve any notice, warning, or error messages.
2. Use realistic device models. Check all component parameters, particularly nonlinear device model parameters, to ensure that they are reasonable.
3. Small floating resistors connected to high impedance nodes can cause convergence difficulties. Avoid very small floating resistors, particularly small parasitic resistors in semiconductors. Instead, use voltage sources or iprobes to measure current.
4. Ensure that a complete set of parasitic capacitors is used on nonlinear devices to avoid jumps in the solution waveforms. On MOS models, specify nonzero source and drain areas.
5. Perform sanity check on the parameter values by using the parameter range checker (use ``+param param-limits-file'' as a command line argument) and heed any warnings. Print the minimum and maximum parameter value by using `info' analysis. Ensure that the bounds given for instance, model, output, temperature-dependent, and operating-point (if possible) parameters are reasonable.

6. Check the direction of both independent and dependent current sources. Convergence problems might result if current sources are connected such that they force current backward through diodes.

7. Enable diagnostic messages by setting option `diagnose=detailed'.
8. Use the `cmin' parameter to install a small capacitor from every node in the circuit to ground. This usually eliminates any jump in the solution.
9. Loosen tolerances, particularly absolute tolerances like `iabstol' (on options statement). If tolerances are set too tight, they might preclude convergence.
10. Try to simplify the nonlinear component models to avoid regions that might contribute to convergence problems in the model.

Conv norm = 1.02e+18, max dI(V1:p) = -45.036 MA, took 70 ms.

Analysis `pss' was terminated prematurely due to an error.

Error found by spectre.
ERROR (SPCRTRF-15024): The pac analysis was skipped because a PSS analysis must be run first.

- - - Updated - - -

Enter it as Unix Command.
HI
I replace ideal switch in N path filter with transmission gate ,I simulated several time
I got error every time
This is my netlist:
do you have any idea?

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// Library name: scfilter_finalproject
// Cell name: fourpathtransmissiongate@idealclck
// View name: schematic
C1 (NM4_D 0) capacitor c=16p
C5 (NM2_D 0) capacitor c=16p
C6 (NM3_D 0) capacitor c=16p
C7 (NM7_D 0) capacitor c=16p
V5 (PM6_G 0) vsource type=pulse delay=1.68n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25p fall=25p width=190p
V4 (PM3_G 0) vsource type=pulse delay=1.2n edgetype=linear val0=0 val1=vdd \
        period=2n rise=25p fall=25p width=190p
V2 (PM2_G 0) vsource type=pulse delay=720p edgetype=linear val0=0 val1=vdd \
        period=2n rise=25p fall=25p width=190p
V0 (PM4q_G 0) vsource type=pulse delay=240p edgetype=linear val0=0 \
        val1=vdd period=2n rise=25p fall=25p width=190.0p
V3 (V3_PLUS 0) vsource type=pulse delay=0 edgetype=linear val0=0 val1=vdd \
        period=2n rise=25p fall=25p width=190.0p
V9 (V9_PLUS 0) vsource type=pulse delay=480p edgetype=linear val0=0 \
        val1=vdd period=2n rise=25p fall=25p width=190p
V10 (V10_PLUS 0) vsource type=pulse delay=960p edgetype=linear val0=0 \
        val1=vdd period=2n rise=25p fall=25p width=190p
V11 (V11_PLUS 0) vsource type=pulse delay=1.44n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25p fall=25p width=190p
R0 (V7_PLUS R0_MINUS) resistor r=50K
V7 (V7_PLUS 0) vsource type=dc pacmag=1 pacphase=0
NM4 (NM4_D V3_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM2 (NM2_D V9_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM3 (NM3_D V10_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM7 (NM7_D V11_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM4q (NM4_D PM4q_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM2 (NM2_D PM2_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM3 (NM3_D PM3_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM6 (NM7_D PM6_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
V1 (vdd! 0) vsource dc=vdd type=dc

 

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(1) Can you get convergence for Transient Analysis ?
(2) rise=25p, fall=25p, width=190p are not appropriate for period=2n
(3) Set long tstab

Show me time domain waveform for V5, V4, V2, V0, V3, V9, V10 and V11 as result of transieent analysis or init tstab for PSS.
 
Last edited:
(1) Can you get convergence for Transient Analysis ?
(2) rise=25p, fall=25p, width=190p are not appropriate for period=2n
(3) Set long tstab

Show me time domain waveform for V5, V4, V2, V0, V3, V9, V10 and V11 as result of transieent analysis or init tstab for PSS.
I have attached
How should I set rise and fall time then ?
 

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the clock is right?
what should be rise time and fall time for this clocks ?I am not sure how should I determine them?
 

Set long tstab

this my clock in same plot (I have attached)
,Actuallt I had increase tstab before ,now is 500u
But I had error,I do not know how high should be tstab?
 

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Show me analysis statements and option statements which you use now.

They was the following.
Code:
simulatorOptions options reltol=1e-3 vabstol=1e-6 iabstol=1e-12 temp=27 \
 tnom=27 scalem=1.0 scale=1.0 gmin=1e-12 rforce=1 maxnotes=5 maxwarns=5 \
 digits=5 cols=80 pivrel=1e-3 sensfile="../psf/sens.output" \
 checklimitdest=psf
 
pss pss fund=500M harms=0 errpreset=conservative tstab=200u
+ maxacfreq=4G annotate=status

Try set errpreset=liberal or errpreset=moderate in pss.
 
Last edited:

Show me analysis statements and option statements which you use now.

They was the following.
Code:
simulatorOptions options reltol=1e-3 vabstol=1e-6 iabstol=1e-12 temp=27 \
 tnom=27 scalem=1.0 scale=1.0 gmin=1e-12 rforce=1 maxnotes=5 maxwarns=5 \
 digits=5 cols=80 pivrel=1e-3 sensfile="../psf/sens.output" \
 checklimitdest=psf
 
 pss pss fund=500M harms=0 errpreset=conservative tstab=200u
 + maxacfreq=4G annotate=status

Try set errpreset=liberal or errpreset=moderate in pss.


this is my "input.scs'
/ Generated for: spectre
// Generated on: Nov 29 11:16:10 2015
// Design library name: scfilter_finalproject
// Design cell name: fourpathtransmissiongate@idealclck
// Design view name: schematic
simulator lang=spectre
global 0 vdd!
parameters vdd=3.3 vt2=vdd/2*(1+1e-3) vt1=vdd/2*(1-1e-3)
include "/CMC/kits/AMSKIT616_GPDK/tech/gpdk045_v_4_0/gpdk045/../models/spectre/gpdk045.scs" section=tt

// Library name: scfilter_finalproject
// Cell name: fourpathtransmissiongate@idealclck
// View name: schematic
C1 (NM4_D 0) capacitor c=16p
C5 (NM2_D 0) capacitor c=16p
C6 (NM3_D 0) capacitor c=16p
C7 (NM7_D 0) capacitor c=16p
V5 (PM6_G 0) vsource type=pulse delay=1.68n edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V4 (PM3_G 0) vsource type=pulse delay=1.2n edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190p
V2 (PM2_G 0) vsource type=pulse delay=720p edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190p
V0 (PM4q_G 0) vsource type=pulse delay=240p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190.0p
V3 (V3_PLUS 0) vsource type=pulse delay=0 edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190.0p
V9 (V9_PLUS 0) vsource type=pulse delay=480p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V10 (V10_PLUS 0) vsource type=pulse delay=960p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V11 (V11_PLUS 0) vsource type=pulse delay=1.44n edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
R0 (V7_PLUS R0_MINUS) resistor r=50K
V7 (V7_PLUS 0) vsource type=dc pacmag=1 pacphase=0
NM4 (NM4_D V3_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM2 (NM2_D V9_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM3 (NM3_D V10_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM7 (NM7_D V11_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM4q (NM4_D PM4q_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM2 (NM2_D PM2_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM3 (NM3_D PM3_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM6 (NM7_D PM6_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
V1 (vdd! 0) vsource dc=vdd type=dc
simulatorOptions options reltol=1e-3 vabstol=1e-6 iabstol=1e-12 temp=27 \
tnom=27 scalem=1.0 scale=1.0 gmin=1e-12 rforce=1 maxnotes=5 maxwarns=5 \
digits=5 cols=80 pivrel=1e-3 sensfile="../psf/sens.output" \
checklimitdest=psf
tran tran stop=100n errpreset=conservative write="spectre.ic" \
writefinal="spectre.fc" annotate=status maxiters=5
finalTimeOP info what=oppoint where=rawfile
modelParameter info what=models where=rawfile
element info what=inst where=rawfile
outputParameter info what=output where=rawfile
designParamVals info what=parameters where=rawfile
primitives info what=primitives where=rawfile
subckts info what=subckts where=rawfile
saveOptions options save=allpub
 

It seems reasonable since they are no-overwrap.
Actually I set errpreset=moderate ,however I got error gain
this is error I got:
Error found by spectre at time = 500.514 us during periodic steady state analysis `pss'.
ERROR (SPECTRE-16192): No convergence achieved with the minimum time step specified. Last acceptable solution computed at 500.002 us.

The values for those nodes that did not converge on the last Newton iteration are given below. The manner in which the convergence criteria were not satisfied is also given.
Failed test: | Value | > RelTol*Ref + AbsTol

Top 10 Solution too large Convergence failure:
V(NM4_D) = 153.224 kV, previously -7.79364 V.
update too large: | 305.447 kV | > 153.227 V + 1 uV
I(V3:p) = -322.586 mA, previously -3.20737 uA.
update too large: | -564.086 mA | > 324.411 uA + 1 pA
I(V5:p) = 56.5878 uA, previously -8.20768 uA.
update too large: | 1.47623 mA | > 1.88165 uA + 1 pA
I(V0:p) = 27.0302 A, previously -21.7084 uA.
update too large: | 8.15898 A | > 27.0321 mA + 1 pA
V(NM7:int_d) = -766.036 mV, previously 704.521 mV.
update too large: | 600 mV | > 4.06647 mV + 1 uV
I(V9:p) = -1.80916 A, previously -3.5096 uA.
update too large: | 169.186 mA | > 1.81099 mA + 1 pA
V(NM4.n1) = 6.03525 V, previously -4.84411 uV.
update too large: | 600 mV | > 9.33569 mV + 1 uV
I(V2:p) = 1.8097 A, previously -22.042 uA.
update too large: | 105.908 mA | > 1.81153 mA + 1 pA
V(NM2_D) = 26.1686 MV, previously -6.32553 V.
update too large: | -1.29285 MV | > 26.1686 kV + 1 uV
V(NM3:int_d) = -11.1658 V, previously 19.0388 V.
update too large: | -600 mV | > 14.4663 mV + 1 uV
Top 10 Residue too large Convergence failure:
V(NM3_D) = -26.5712 MV, previously 19.0388 V.
residue too large: | 1.27072 GA | > 1.27072 MA + 1 pA
V(NM2_D) = 26.1686 MV, previously -6.32553 V.
residue too large: | -1.32185 GA | > 1.32185 MA + 1 pA
V(PM3:int_d) = 3.98436 V, previously 19.0388 V.
residue too large: | -2.18674e+18 A | > 2.18674e+15 A + 1 pA
V(PM3:int_s) = -144.01 V, previously 495.513 mV.
residue too large: | -1.35617e+18 A | > 1.35617e+15 A + 1 pA
V(PM6.n1) = 38.1517 V, previously -12.4115 uV.
residue too large: | -190.643e+15 A | > 190.643 TA + 1 pA
V(PM2.n1) = 13.0033 V, previously -33.3541 uV.
residue too large: | -33.0786e+15 A | > 33.0786 TA + 1 pA
V(PM4q.n1) = 3.25305 V, previously -32.8493 uV.
residue too large: | -33.0802e+15 A | > 33.0802 TA + 1 pA
V(NM7.n1) = -705.636 V, previously 826.922 mV.
residue too large: | 56.7315e+18 A | > 56.7315e+15 A + 1 pA
V(NM2.n1) = 30.0352 V, previously -5.30054 uV.
residue too large: | -1.86119e+18 A | > 1.86119e+15 A + 1 pA
V(NM4.n1) = 6.03525 V, previously -4.84411 uV.
residue too large: | -1.52517e+18 A | > 1.52517e+15 A + 1 pA


The following set of suggestions might help you avoid convergence difficulties.

1. Evaluate and resolve any notice, warning, or error messages.
2. Use realistic device models. Check all component parameters, particularly nonlinear device model parameters, to ensure that they are reasonable.
3. Small floating resistors connected to high impedance nodes can cause convergence difficulties. Avoid very small floating resistors, particularly small parasitic resistors in semiconductors. Instead, use voltage sources or iprobes to measure current.
4. Ensure that a complete set of parasitic capacitors is used on nonlinear devices to avoid jumps in the solution waveforms. On MOS models, specify nonzero source and drain areas.
5. Perform sanity check on the parameter values by using the parameter range checker (use ``+param param-limits-file'' as a command line argument) and heed any warnings. Print the minimum and maximum parameter value by using `info' analysis. Ensure that the bounds given for instance, model, output, temperature-dependent, and operating-point (if possible) parameters are reasonable.

6. Check the direction of both independent and dependent current sources. Convergence problems might result if current sources are connected such that they force current backward through diodes.

7. Enable diagnostic messages by setting option `diagnose=detailed'.
8. Use the `cmin' parameter to install a small capacitor from every node in the circuit to ground. This usually eliminates any jump in the solution.
9. Loosen tolerances, particularly absolute tolerances like `iabstol' (on options statement). If tolerances are set too tight, they might preclude convergence.
10. Try to simplify the nonlinear component models to avoid regions that might contribute to convergence problems in the model.

Conv norm = 33.4e+15, max dI(V1:p) = -45.036 MA, took 80 ms.

Analysis `pss' was terminated prematurely due to an error.

Error found by spectre.
ERROR (SPCRTRF-15024): The pac analysis was skipped because a PSS analysis must be run first.

do you have any idea?

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It seems reasonable since they are no-overwrap.
this is my "input.scs"
// Generated for: spectre
// Generated on: Nov 29 11:16:10 2015
// Design library name: scfilter_finalproject
// Design cell name: fourpathtransmissiongate@idealclck
// Design view name: schematic
simulator lang=spectre
global 0 vdd!
parameters vdd=3.3 vt2=vdd/2*(1+1e-3) vt1=vdd/2*(1-1e-3)
include "/CMC/kits/AMSKIT616_GPDK/tech/gpdk045_v_4_0/gpdk045/../models/spectre/gpdk045.scs" section=tt

// Library name: scfilter_finalproject
// Cell name: fourpathtransmissiongate@idealclck
// View name: schematic
C1 (NM4_D 0) capacitor c=16p
C5 (NM2_D 0) capacitor c=16p
C6 (NM3_D 0) capacitor c=16p
C7 (NM7_D 0) capacitor c=16p
V5 (PM6_G 0) vsource type=pulse delay=1.68n edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V4 (PM3_G 0) vsource type=pulse delay=1.2n edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190p
V2 (PM2_G 0) vsource type=pulse delay=720p edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190p
V0 (PM4q_G 0) vsource type=pulse delay=240p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190.0p
V3 (V3_PLUS 0) vsource type=pulse delay=0 edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190.0p
V9 (V9_PLUS 0) vsource type=pulse delay=480p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V10 (V10_PLUS 0) vsource type=pulse delay=960p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V11 (V11_PLUS 0) vsource type=pulse delay=1.44n edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
R0 (V7_PLUS R0_MINUS) resistor r=50K
V7 (V7_PLUS 0) vsource type=dc pacmag=1 pacphase=0
NM4 (NM4_D V3_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM2 (NM2_D V9_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM3 (NM3_D V10_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM7 (NM7_D V11_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM4q (NM4_D PM4q_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM2 (NM2_D PM2_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM3 (NM3_D PM3_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM6 (NM7_D PM6_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
V1 (vdd! 0) vsource dc=vdd type=dc
simulatorOptions options reltol=1e-3 vabstol=1e-6 iabstol=1e-12 temp=27 \
tnom=27 scalem=1.0 scale=1.0 gmin=1e-12 rforce=1 maxnotes=5 maxwarns=5 \
digits=5 cols=80 pivrel=1e-3 sensfile="../psf/sens.output" \
checklimitdest=psf
pss pss fund=500M harms=0 errpreset=moderate tstab=500u
+ tstabmethod=gear2 maxacfreq=5G maxperiods=40 annotate=status
pac pac start=50M stop=5G dec=1000
+ values=[10-50-100-150-250-300-350-400-450-500] maxsideband=0
+ annotate=status
modelParameter info what=models where=rawfile
element info what=inst where=rawfile
outputParameter info what=output where=rawfile
designParamVals info what=parameters where=rawfile
primitives info what=primitives where=rawfile
subckts info what=subckts where=rawfile
saveOptions options save=allpub

- - - Updated - - -

this is netlist:

// Library name: scfilter_finalproject
// Cell name: fourpathtransmissiongate@idealclck
// View name: schematic
C1 (NM4_D 0) capacitor c=16p
C5 (NM2_D 0) capacitor c=16p
C6 (NM3_D 0) capacitor c=16p
C7 (NM7_D 0) capacitor c=16p
V5 (PM6_G 0) vsource type=pulse delay=1.68n edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V4 (PM3_G 0) vsource type=pulse delay=1.2n edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190p
V2 (PM2_G 0) vsource type=pulse delay=720p edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190p
V0 (PM4q_G 0) vsource type=pulse delay=240p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190.0p
V3 (V3_PLUS 0) vsource type=pulse delay=0 edgetype=linear val0=0 val1=vdd \
period=2n rise=25p fall=25p width=190.0p
V9 (V9_PLUS 0) vsource type=pulse delay=480p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V10 (V10_PLUS 0) vsource type=pulse delay=960p edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
V11 (V11_PLUS 0) vsource type=pulse delay=1.44n edgetype=linear val0=0 \
val1=vdd period=2n rise=25p fall=25p width=190p
R0 (V7_PLUS R0_MINUS) resistor r=50K
V7 (V7_PLUS 0) vsource type=dc pacmag=1 pacphase=0
NM4 (NM4_D V3_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM2 (NM2_D V9_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM3 (NM3_D V10_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM7 (NM7_D V11_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM4q (NM4_D PM4q_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM2 (NM2_D PM2_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM3 (NM3_D PM3_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM6 (NM7_D PM6_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
V1 (vdd! 0) vsource dc=vdd type=dc
 

parameters vdd=3.3 vt2=vdd/2*(1+1e-3) vt1=vdd/2*(1-1e-3)
include "/CMC/kits/AMSKIT616_GPDK/tech/gpdk045_v_4_0/gpdk045/../models/spectre/gpdk045.scs" section=tt
It seems you use Cadence 45nm Generic PDK. Right ?
Why do you set vdd as 3.3V ?

"g45n1svt" and "g45p1svt" are High Voltage MOSFET ?

You use MOSFET of L=100nm.
I can't believe proper vdd value is 3.3V.
 
Last edited:

It seems you use Cadence 45nm Generic PDK. Right ?
Why do you set vdd as 3.3V ?

"g45n1svt" and "g45p1svt" are High Voltage MOSFET ?

You use MOSFET of L=100nm.
I can't believe proper vdd value is 3.3V.

Yes the technology that I use is CMOS 45nm
I just set vdd as 3.3 by chance ,do you think if I change vdd value problem will be solve??
every simulation take at least 5 hour to run

- - - Updated - - -

It seems you use Cadence 45nm Generic PDK. Right ?
Why do you set vdd as 3.3V ?

"g45n1svt" and "g45p1svt" are High Voltage MOSFET ?

You use MOSFET of L=100nm.
I can't believe proper vdd value is 3.3V.
Also I read somewhere that if you reduce fall time and rise time ,and increase resistance, this problem will be solve and I reduce fall time and rise time from 25p to 25f and change resistance from 50K to 100K
now there is no error ,however the result does not look right
I have attached re result

- - - Updated - - -

Yes the technology that I use is CMOS 45nm
I just set vdd as 3.3 by chance ,do you think if I change vdd value problem will be solve??
every simulation take at least 5 hour to run

- - - Updated - - -


Also I read somewhere that if you reduce fall time and rise time ,and increase resistance, this problem will be solve and I reduce fall time and rise time from 25p to 25f and change resistance from 50K to 100K
now there is error ,however the result does not look right
I have attached re result
this is my "input.scs'

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/ Generated for: spectre
// Generated on: Nov 30 10:31:13 2015
// Design library name: scfilter_finalproject
// Design cell name: fourpathtransmissiongate@idealclck
// Design view name: schematic
simulator lang=spectre
global 0 vdd!
parameters vdd=3.3 vt2=vdd/2*(1+1e-3) vt1=vdd/2*(1-1e-3)
include "/CMC/kits/AMSKIT616_GPDK/tech/gpdk045_v_4_0/gpdk045/../models/spectre/gpdk045.scs" section=tt
 
// Library name: scfilter_finalproject
// Cell name: fourpathtransmissiongate@idealclck
// View name: schematic
C1 (NM4_D 0) capacitor c=16p
C5 (NM2_D 0) capacitor c=16p
C6 (NM3_D 0) capacitor c=16p
C7 (NM7_D 0) capacitor c=16p
V5 (PM6_G 0) vsource type=pulse delay=1.75n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V4 (PM3_G 0) vsource type=pulse delay=1.25n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V2 (PM2_G 0) vsource type=pulse delay=750p edgetype=linear val0=0 val1=vdd \
        period=2n rise=25f fall=25f width=249p
V0 (PM4q_G 0) vsource type=pulse delay=250p edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249.0p
V3 (V3_PLUS 0) vsource type=pulse delay=0 edgetype=linear val0=0 val1=vdd \
        period=2n rise=25f fall=25f width=249.0p
V9 (V9_PLUS 0) vsource type=pulse delay=500p edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V10 (V10_PLUS 0) vsource type=pulse delay=1n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V11 (V11_PLUS 0) vsource type=pulse delay=1.5n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
R0 (V7_PLUS R0_MINUS) resistor r=100K
V7 (V7_PLUS 0) vsource type=dc pacmag=1 pacphase=0
NM4 (NM4_D V3_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM2 (NM2_D V9_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM3 (NM3_D V10_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM7 (NM7_D V11_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM4q (NM4_D PM4q_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM2 (NM2_D PM2_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM3 (NM3_D PM3_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM6 (NM7_D PM6_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
V1 (vdd! 0) vsource dc=vdd type=dc
simulatorOptions options reltol=1e-3 vabstol=1e-6 iabstol=1e-12 temp=27 \
    tnom=27 scalem=1.0 scale=1.0 gmin=1e-12 rforce=1 maxnotes=5 maxwarns=5 \
    digits=5 cols=80 pivrel=1e-3 sensfile="../psf/sens.output" \
    checklimitdest=psf 
pss  pss  fund=500M  harms=0  errpreset=moderate  tstab=500u
+    tstabmethod=gear2  maxacfreq=5G  maxperiods=40  annotate=status
pac  pac  start=50M  stop=5G  dec=1000
+    values=[10-50-100-150-250-300-350-400-450-500]  maxsideband=0
+    annotate=status
modelParameter info what=models where=rawfile
element info what=inst where=rawfile
outputParameter info what=output where=rawfile
designParamVals info what=parameters where=rawfile
primitives info what=primitives where=rawfile
subckts info what=subckts  where=rawfile
saveOptions options save=allpub



- - - Updated - - -

this is netlist:

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// Library name: scfilter_finalproject
// Cell name: fourpathtransmissiongate@idealclck
// View name: schematic
C1 (NM4_D 0) capacitor c=16p
C5 (NM2_D 0) capacitor c=16p
C6 (NM3_D 0) capacitor c=16p
C7 (NM7_D 0) capacitor c=16p
V5 (PM6_G 0) vsource type=pulse delay=1.75n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V4 (PM3_G 0) vsource type=pulse delay=1.25n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V2 (PM2_G 0) vsource type=pulse delay=750p edgetype=linear val0=0 val1=vdd \
        period=2n rise=25f fall=25f width=249p
V0 (PM4q_G 0) vsource type=pulse delay=250p edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249.0p
V3 (V3_PLUS 0) vsource type=pulse delay=0 edgetype=linear val0=0 val1=vdd \
        period=2n rise=25f fall=25f width=249.0p
V9 (V9_PLUS 0) vsource type=pulse delay=500p edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V10 (V10_PLUS 0) vsource type=pulse delay=1n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
V11 (V11_PLUS 0) vsource type=pulse delay=1.5n edgetype=linear val0=0 \
        val1=vdd period=2n rise=25f fall=25f width=249p
R0 (V7_PLUS R0_MINUS) resistor r=100K
V7 (V7_PLUS 0) vsource type=dc pacmag=1 pacphase=0
NM4 (NM4_D V3_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM2 (NM2_D V9_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM3 (NM3_D V10_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
NM7 (NM7_D V11_PLUS R0_MINUS 0) g45n1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM4q (NM4_D PM4q_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM2 (NM2_D PM2_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM3 (NM3_D PM3_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
PM6 (NM7_D PM6_G R0_MINUS vdd!) g45p1svt w=(24u) l=100n nf=40 as=1.992p \
        ad=1.92p ps=31.84u pd=30.4u nrd=3.33333m nrs=3.45833m sa=140n \
        sb=140n sd=160n sca=83.83838 scb=0.07030 scc=0.00923 m=(1)
V1 (vdd! 0) vsource dc=vdd type=dc

 

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