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In this case the Q of the ckt is unaffected, because the source is a current source, i.e. an infinite impedance to AC, therefore resonant currents do not flow in it and it contributes no damping effect or loss in Q, the result of the extra R in series with i(t) is to reduce the volts applied to the rest of the circuit, only. Different if you are driving with a voltage source...
In general, you can find the Q of such circuits (involving L, C and R) using the corresponding vector/phasor diagram.
The resulting total current I will be not in phase with the applied overall voltage V.
Then, the quality factor of the circuit is Q=tan(phi) if phi is the phase angle between V and I.