aersoy said:it means that the voltage of Vce is 0.6 in saturation mode of bjt.
if
Ib>=βIc BJT is in saturation
in active region
Ib = βIc
remove the bjt from the circuit then calculate the voltage across Vbe if Vbe is smaller than 0.7 (or threshold voltage of bjt) the BJT is in cutoff mode
yes ur rigth i wrote the formula wrong and i am correcting the mistkepuneet bansal said:BJT is in sat when Ic<(β×Ib).
for a BJT is to in saturation, we have to apply Vbe atleast .75V .
We have
σ = (Ic÷βIb)
When σ<1, then we say BJT is in Saturation.
As the value of σ becomes less than 1 i.e. σ<<1
BJT goes deeper in to saturation.
Generally, Vce(Sat) is 0.1V or 0.2V
Vce(sat) is directly proportionally to Vt(=Thermal Voltage)
Cheers
Puneet Bansal :idea:
Added after 3 minutes:
aersoy said:it means that the voltage of Vce is 0.6 in saturation mode of bjt.
if
Ib>=βIc BJT is in saturation
in active region
Ib = βIc
remove the bjt from the circuit then calculate the voltage across Vbe if Vbe is smaller than 0.7 (or threshold voltage of bjt) the BJT is in cutoff mode
My Dear friend
u hv written Ib>=βIc !
It is wrong dear.
we have Ic=βIb
for further enquiry
check my answer below !
CHEERS
Puneet Bansal
Yes that's true. It's confusing but the MOS saturated operation is equivalent to the BJT active region. The BJT saturated region is part of the MOSFET linear (triode) region. Just something they did to keep you on your toes.Sorry I did not understand. BJT in saturation == MOS in triode. ..............................
No. Vce(sat) is similar to Vds in the FET linear region with a large Vgs voltage (well above the Vgs(thres). See aboveOriginally posted by wky
Vce(sat) is analogous to Vds(sat)
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