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kolahalb

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I am to show that Ñ.(A+B)=0 if
ÑxAis not=0
ÑxBis not=0

I suppose this is not a valid question.You please check.If it is a correct one then tell me how to start with.

Added after 7 minutes:

OK,that was a notation problem.
What we are given is that curl A or curl B are not equal to zero.
 

please refine your question. tell us what eveything name means. then maybe i can help.

Ñ.(A+B)=?
A=?
B=?
ÑxAis=?
ÑxBist=?


mayyan
 

OK,A and B are vector fields having curl equal to zero.
We are to show div of (A+B)=0

Possibly the question is wrong.Except from some specific example it is not correct.Hence,cannot be proved.
Actually,since I wanted someone to say with me that this is wrong, posted this over here.But,unfortunately,the curl and div signs did not appear clearly.
 

div(A+B) = div A + div B = 0, so we must have div A = -div B or A = -B, but the information about their curl tells us nothing about their divergence, so this is not true. div rot A = 0, but this does not mean div A = 0.
 

I could not understand the symbols you have used. Please clarify them.
 

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