May 12, 2008 #1 M mouzid Full Member level 5 Joined Jun 22, 2007 Messages 248 Helped 9 Reputation 18 Reaction score 0 Trophy points 1,296 Activity points 2,876 Hello, I was asked this question in an interview. What is the gain of the charge pump in he figure ? My response was Kcp=Ic/(2*Pi) What is the Gain of the Charge pump if we retrieve the intverter ? My reply was Kcp=Ic*((2*pi)-1)/2*pi Is my replies trues ? Thanks in advance.
Hello, I was asked this question in an interview. What is the gain of the charge pump in he figure ? My response was Kcp=Ic/(2*Pi) What is the Gain of the Charge pump if we retrieve the intverter ? My reply was Kcp=Ic*((2*pi)-1)/2*pi Is my replies trues ? Thanks in advance.
May 13, 2008 #2 AdvaRes Advanced Member level 4 Joined Feb 14, 2008 Messages 1,163 Helped 113 Reputation 220 Reaction score 51 Trophy points 1,328 Location At home Activity points 7,442 1- You're rigth K=Ic/(2*pi) 2- I'm not sure for the second but I thing K=Ic-[Ic*(pi-1)/(2*pi)]
May 13, 2008 #3 T taofeng Advanced Member level 4 Joined Mar 21, 2006 Messages 104 Helped 1 Reputation 2 Reaction score 0 Trophy points 1,296 Activity points 2,021 AdvaRes said: 1- You're rigth K=Ic/(2*pi) 2- I'm not sure for the second but I thing K=Ic-[Ic*(pi-1)/(2*pi)] Click to expand... the first I agree, but I do not fully get the second ? does it also depend on the delay of the inverter ? can anyone explain it ?
AdvaRes said: 1- You're rigth K=Ic/(2*pi) 2- I'm not sure for the second but I thing K=Ic-[Ic*(pi-1)/(2*pi)] Click to expand... the first I agree, but I do not fully get the second ? does it also depend on the delay of the inverter ? can anyone explain it ?