Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronic Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

impulse sensitivity function for ring oscillators

Status
Not open for further replies.

ppat2006

Member level 2
Joined
Aug 14, 2010
Messages
43
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,286
Location
india
Activity points
1,585
does anybody know how to obtain impulse sensitivity function for single ended ring oscillators. the formula is

isf = f'(x)/[f'(x)2 + f''(x)2] where f'(x) is derivative of output voltage function
of ring osc and f''(x) is double derivative of output voltage function of ring osc.


for eg for colpitt osc, f(x) = sin(x) so we can calculate derivative and obtain isf plot.

so i dont know how to obtain f(x) for single ended 5 stage ring osc?
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Top