echoas
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Now, I'm reading the book"STA for Nanometer Design". In Chp3 about the setup and holdtime check.
The Original sentences in this book in page 64:
Notice that some of the hold values in the example above are negative. This is acceptable and normally happens when the path from the pin of the flip-flop to the internal latch point for the data is longer than the corresponding path for the clock. Thus, a negative hold check implies that the data pin of the flip-flop can change ahead of the clock pin and still meet the hold time
check.
Now, I'm confused about the above sentence. It said that the data path is longer than the clock. why ahead? I think it produced by the delay of clock resulting in ahead.
anyone can explain it in details?
regards!
The Original sentences in this book in page 64:
Notice that some of the hold values in the example above are negative. This is acceptable and normally happens when the path from the pin of the flip-flop to the internal latch point for the data is longer than the corresponding path for the clock. Thus, a negative hold check implies that the data pin of the flip-flop can change ahead of the clock pin and still meet the hold time
check.
Now, I'm confused about the above sentence. It said that the data path is longer than the clock. why ahead? I think it produced by the delay of clock resulting in ahead.
anyone can explain it in details?
regards!
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