Kindly explain how we are supposed to explain an invisible circuit.
yes in amplifier stage there are FETs in that circuit. Can you explain the working of SIC diode in the circuit?what you call an “amplifier” looks to me like a box with the letters F E T in it. Regardless, the current in the inductors does not come from the amplifier, it comes from the power Supply by the charging and discharging of the cap and inductors.
Sir kindly explain the circuitry in detail and in simple way.When transistors(Q5/ Q6/ Q7) are turned on its mean 0 volt (ground volt )at inductor L1 and Sic diode. kindly explain the working of the circuit.the diode clamps the inductive flyback voltage when an FET turns off.
Sir The complete circuit is attach herewith..kindly explain the working of whole circuit..There's not consistent circuit schematic yet that can be explained. The connection of "amplifier# FETs isn't clear. If 400V is the power supply, where's the circuit output, what's the load.
Kindly explain the whole circuit working. For example when FET is closed mean 0 volt on drain then how inductor will store energy etc. AS dc is applied then sic diode is reversed biased and capacitor will act as open circuit due to DC supply (400 v). Then how first stage step down and provide 0 to 400 volt variable DC?Thanks, now the circuit makes sense. The left part is a three phase buck converter, reducing 400 V input to 0 - 400 V fed to the full bridge on the right. Unlike the typical buck converter with common negative ground this circuit has common positive node and respectively position of transistor and diode flipped.
Kindly explain the working of the circuit especially the first section of the circuitThe reference to fly-back clamp misses the point. Clamping is a side effect, the circuit purpose is voltage down conversion.
It is forum for all to share the technical problems. If someone is not genius like you then please let him to ask again and again so that concept may be cleared to him. Hope you will understand my point.You’re awfully demanding. We have explained the purpose of the diodes, as you asked. Fvm has explained the basic function of the circuit. Danadakk has actually gone to the trouble of simulating the inductive flyback for you.
Maybe it’s time for you to read a book or do some research of your own, instead of insisting we do a complete circuit analysis for you.
Thank you Sir, the main confusion in my circuit was the polarity of diode which compel me to ask the functionality of the circuit. anyways thank youThe converter topology is (multi-phase) buck converter. As for the basic theory of operation and waveforms, you can refer to this link. https://en.wikipedia.org/wiki/Buck_converter#Concept
Polarity is however flipped in your circuit, as shown in the below schematic
View attachment 168598
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