Jan 5, 2016 #1 S shemo Advanced Member level 4 Joined Apr 26, 2002 Messages 105 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,296 Activity points 709 1) on this diagram when read is high, it will pull the bit line to high. How does register as a read? 2) on write , and let's say /D is high that will pull the bit line low. On both case, where does the bit line go? seems like its either pull up or pull down. I don't see bit line being present to an output.
1) on this diagram when read is high, it will pull the bit line to high. How does register as a read? 2) on write , and let's say /D is high that will pull the bit line low. On both case, where does the bit line go? seems like its either pull up or pull down. I don't see bit line being present to an output.
Jan 5, 2016 #2 G gs65 Member level 1 Joined Sep 9, 2014 Messages 39 Helped 11 Reputation 22 Reaction score 11 Trophy points 8 Location Bangalore,India Activity points 199 Hi, In the diagram that you have attached ,there is no read circuitary. to read the data from sram , we use sense amplifiers (differential amplifier). bit lines will be given as input to sense amp. the output of sense amp will be your dout
Hi, In the diagram that you have attached ,there is no read circuitary. to read the data from sram , we use sense amplifiers (differential amplifier). bit lines will be given as input to sense amp. the output of sense amp will be your dout