help soving the intgeral equation

[adnan012]

hi,

the second equation comes after solving the first equation. I need the steps involved. Can anyone help me?

 

[albbg]

First of all remember that ln(1/x)=-log(x). Second \[\Gamma\] doesn't depends from frequecy then it can be brought out from the integral.
Thus the integral result is simply \[\omega\]b-\[\omega\]a.
This means the equation can be rewritten as:

-ln|gamma|*(wb-wa)=pi/(R0*C1) that means:

ln|gamma|=-pi/[(wb-wa)*(R0*C1)]

that is:

|gamma|=exp{-pi/[(wb-wa)*(R0*C1)]}

 

[adnan012]

Thank you very much.