Jan 13, 2008 #1 K kavitha_rapolu Junior Member level 3 Joined Jan 4, 2008 Messages 26 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,460 rl with switch In the attached figure with rl circuit and switch , at t =0- iL(0-) is 5ma , but why is the current at t =0+ ( ie when the switch is open ) iL(0+)= 0A ? Why is it violating the rule that current across the inductor can't change instantaneously ?
rl with switch In the attached figure with rl circuit and switch , at t =0- iL(0-) is 5ma , but why is the current at t =0+ ( ie when the switch is open ) iL(0+)= 0A ? Why is it violating the rule that current across the inductor can't change instantaneously ?
Jan 13, 2008 #2 Old Nick Advanced Member level 1 Joined Sep 14, 2007 Messages 479 Helped 68 Reputation 136 Reaction score 18 Trophy points 1,298 Activity points 4,243 Re: rl with switch You'll want to check out the voltage accross the inductor when you flip the switch!!
Re: rl with switch You'll want to check out the voltage accross the inductor when you flip the switch!!
Jan 13, 2008 #3 K kavitha_rapolu Junior Member level 3 Joined Jan 4, 2008 Messages 26 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,460 Re: rl with switch isn't the voltage across the inductor 0 in both the cases (ie when the switch is first closed and then open) ? But why is the current at t=0+ 0A ?
Re: rl with switch isn't the voltage across the inductor 0 in both the cases (ie when the switch is first closed and then open) ? But why is the current at t=0+ 0A ?