Kral
Advanced Member level 4
I need the Inverse LaPlace transform of G(s) = s/((s-a)^2 + b^2), where a, b are constants. I can't find it in the tables. However I can find the Inverse transform of G(s) = 1/((s-a)^2 + b^2). It's (1/b)(exp(at)(sin(bt)). I know that multiplication by s in the s domain is equivalent to differentiating in the time domain. So I found the inverse transform by differentiating (1/b)(exp(at)(sin(bt)). Is this valid?
Thanks
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