With 3.3V from your micro on the base the emitter can only be 3.3+- .8 or so, i.e. 2.5 or 4.1V or you will destroy the transistor.
If you want your emitter to switch , say +12V/0V then the first stage is to amplify the 3.3V. When its delivering current the output voltage will be less then 12V
Frank
And therefore the voltage at the base needs to be about +12V of OFF and about +11.3V for ON. That´s the difficulty. (Voltages are not absolute! They vary with supply voltage and V_BE of the transistor)
*****
Any load can be switched low side or high side. Low side is easier. Why do you insist in high side switching and PNP?
If using the PNP as a switch then the value of the 2K resistor in Brad's circuit should be selected so that the PNP base current is at least 1/10th of the collector load current to insure that the PNP is fully on and saturated when switched.
Basically this means the 2k resistor should be no larger than 10 times the load resistance.
Thus the 2k resistor should actually be ≦240Ω and the 30k resistor should be ≦1.3kΩ for the 24Ω load.