BartlebyScrivener
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On p63 a method is introduced for formulating the gain by inspection. It is said that
'The magnitude of the gain is the resistance seen at the drain node divided by the total resistance in the source path'
This sounds great ... but other than his simple example I cannot get it to work!!
For example, for a source degenerate circuit including ro and gmb I would say that the total resistance in the source path is
Rs + ( 1/gm // 1/gmb // ro )
Which does not give me the value of gm calculated in equation (3.55)
I get \[\frac{ro(gm+gmb)+1}{ro[Rs(gm+gmb)+1] + Rs }\]
Which is incredibly close ... but no cigar. It should be
\[\frac{ gm*ro}{ ro[Rs(gm+gmb)+1] + Rs}\]
Any clue as to what I am doing wrong? It looks so easy!!!
'The magnitude of the gain is the resistance seen at the drain node divided by the total resistance in the source path'
This sounds great ... but other than his simple example I cannot get it to work!!
For example, for a source degenerate circuit including ro and gmb I would say that the total resistance in the source path is
Rs + ( 1/gm // 1/gmb // ro )
Which does not give me the value of gm calculated in equation (3.55)
I get \[\frac{ro(gm+gmb)+1}{ro[Rs(gm+gmb)+1] + Rs }\]
Which is incredibly close ... but no cigar. It should be
\[\frac{ gm*ro}{ ro[Rs(gm+gmb)+1] + Rs}\]
Any clue as to what I am doing wrong? It looks so easy!!!