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doubt regarding pipelined adc..

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amriths04

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i have to design a 10 bit resolution , a 1.5 bit per stage 100MEGA samples per second pipelined adc. i decided to use opamp sharing technique..

i had written my design equations, please tell whether i am right or wrong..

first i chose the sampling cap and feedback cap values in the following manner.

4kt/Cs << (del)^2 / 12... where del = step size = 2Vref/(2^10 - 1 )..
Vref=1V(pp,diff).

i got Cs >> 56fF. so i chose Cs = 400fF.

since i want my closed loop gain(Acl) as 2, i took feedback factor(beta) = 0.5.
so Cs = Ci for beta to be 0.5.

next how should i proceed? is all what i did till now right?

------- another doubt is that i had taken my step-size(in noise calculation) to be 2Vref/(2^10 - 1).. but in a single stage the step size should be 2*Vref/(2^2 - 1) only right?

please correct me if i am wrong..

thank you in advance,
 

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