unterminated power divider
Hello!
Thanks a lot!
But with a triangular configuration I get additional waveform dispersion because the wave can travel on two paths: one path directly over one resistor (50 Ohm), the other over two resistors in series (2x 50 Ohm).
The total inductivity is smaller (2/3) than that of a single resistor in a triangular configuration.
With a star configuration there are always two resistors in series the wave must travel along. As it is a single path only there is no waveform dispersion due to different paths, but the inductivity is doubled (two resistors in series).
Is having a lower inductivity more important than having a single path?
CU
Added after 23 minutes:
IanP said:
"Frequently Asked Questions about Power Splitters & Dividers. . ."
What I still don't understand is this sentence in the document:
"Power dividers should not be used in ratio and leveling loop application because a mismatch condition of nominally 3:1 would exist."
If I have a power divider (triangular configuration) with three resistors of 50 Ohm each, and I terminate two of the ports with 50 Ohm, then I can see a load of 50 Ohm on the unterminated port. (BTW: in this configuration the resistor across the two terminated ports doesn't carry any current because there is no voltage difference across it.)
So why is there a 3:1 mismatch condition?
CU