[PIC] Compare two 4 bit numbers using PIC16f676 in Assembly Language

[coder123]

I nedd help with the following problem statement, Thank you

Suppose there are two 4 bit numbers X and Y ( 0000,0001,....) .... if X>Y, Z=1 else Z=0

How do i code this is PIC16f676

 

[bigdogguru]

What programming language are you using to code?

For C, you could use the ternary operator:

mask = 0x0F;

Z = (X & mask) > (Y & mask) ? 1 : 0;

A bitwise mask is used to ensure the first four bits of each value are cleared.

Example Code for PC:

---

Code C - [expand]
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#include <stdio.h>
 
 
int main(void)
{
    unsigned char X = 5;
    unsigned char Y = 3;
    unsigned char Z;
    unsigned char mask = 0x0F;
 
    Z = (X & mask) > (Y & mask) ?  1 :  0;
 
    if(Z)
    {
        printf("X is greater than Y\n");
    }
    else
    {
        printf("Y is greater or equal to X\n");
    }
 
    return 0;
}

---

BigDog

 

[coder123]

I need the code in assembly language.
I also need the code where you initialise the input and output ports .

Thanks a lot

 

[KlausST]

Hi,

I also need the code where you initialise the input and output ports .

you have to tell use where are the inputs and outputs.

Klaus

 

[coder123]

Just tell me the logic how will you compare two binary numbers in assembly language.
(without using and <, > or equal sign )
Binary comparison

If you can help with the assmebly language code that will be great

 

[betwixt]

Subtract one from the other:

movlw number1
movwf SomeLocation
movlw number2
subwf Somelocation,f

Then check the STATUS register. The Z flag will be set if the values are equal and if it isn't set, the C flag tells you which number is larger.

Brian.