Jan 10, 2005 #1 F fighter5555 Junior Member level 2 Joined Feb 8, 2002 Messages 24 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 91 Fourier series It is possible to get the trigonometric series from complex fourier series
Jan 10, 2005 #2 A aboozar.hamidipoor Full Member level 3 Joined Dec 21, 2004 Messages 152 Helped 17 Reputation 34 Reaction score 7 Trophy points 1,298 Location Iran Activity points 1,623 Re: Fourier series It is clear that it's possible easily by Euler Identity .
Jan 14, 2005 #3 M mayyan Full Member level 2 Joined Aug 18, 2001 Messages 130 Helped 12 Reputation 24 Reaction score 5 Trophy points 1,298 Location israel Activity points 770 Re: Fourier series yes its posible. most mathematical books with forier analysis in it has that proof. if you still cant find it let me know and i will post it. maayan
Re: Fourier series yes its posible. most mathematical books with forier analysis in it has that proof. if you still cant find it let me know and i will post it. maayan
Jan 22, 2005 #4 F fighter5555 Junior Member level 2 Joined Feb 8, 2002 Messages 24 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 91 Re: Fourier series mayyan can you pls post the solution thks
Jan 23, 2005 #5 D DrDolittle Full Member level 3 Joined Sep 24, 2004 Messages 162 Helped 5 Reputation 10 Reaction score 1 Trophy points 1,298 Location Within arm's reach Activity points 1,443 Re: Fourier series substitute cos Φ = e(iΦ) + e(-iΦ) / 2 sin Φ = e(iΦ) - e(-iΦ) / 2 Regards drdolittle
Re: Fourier series substitute cos Φ = e(iΦ) + e(-iΦ) / 2 sin Φ = e(iΦ) - e(-iΦ) / 2 Regards drdolittle
Jan 23, 2005 #6 B baluba Junior Member level 1 Joined Feb 25, 2004 Messages 19 Helped 2 Reputation 4 Reaction score 1 Trophy points 1,283 Activity points 181 Re: Fourier series DrDolittle said: substitute cos Φ = e(iΦ) + e(-iΦ) / 2 sin Φ = e(iΦ) - e(-iΦ) / 2 Regards drdolittle Click to expand... the second identity is in fact sin Φ = e(iΦ) - e(-iΦ) / 2i regards, baluba
Re: Fourier series DrDolittle said: substitute cos Φ = e(iΦ) + e(-iΦ) / 2 sin Φ = e(iΦ) - e(-iΦ) / 2 Regards drdolittle Click to expand... the second identity is in fact sin Φ = e(iΦ) - e(-iΦ) / 2i regards, baluba
Jan 24, 2005 #7 D DrDolittle Full Member level 3 Joined Sep 24, 2004 Messages 162 Helped 5 Reputation 10 Reaction score 1 Trophy points 1,298 Location Within arm's reach Activity points 1,443 Re: Fourier series Oh yeah,thanx for that note. i forgot to add that i factor. Regards drdolittle
May 19, 2005 #8 T tara1 Newbie level 2 Joined May 3, 2005 Messages 2 Helped 1 Reputation 2 Reaction score 0 Trophy points 1,281 Activity points 1,376 Fourier series h**p://satyap.csoft.net/ss.pdf