Spoerle
Junior Member level 2
According to wiki the cell voltage is (say) 2.4 V and the current density is 0.3A/cm2 Electrolyzer cell resistance = anode resistance + cathode resistance + electrolyte resistance Assume that the electrodes are made of stainless steel 316L with a thickness of 0.3 mm and the electrolyte layer between them is 2 mm. The operating temperature is 60C and the electrolyte is 25% KOH.
Resistivity of steel 316L for 60C = 7,67232E-06 Ohm*mm
Specific electrical resistance 25% KOH for 60C = 9,657298288 Ohm*mm
Assume square electrodes 100x100mm, 30% of the area is for bubbles and free space for gas removal, i.e. the area of the electrodes is 7000mm2.
R electrodes = 2 * (7,67232E-06*0,3/7000) = 6,57627E-10 Ohm
R electrolyte= 9,657298288*2/7000= 2,759228E-03 Ohm
R cell= 5,51846E-03 Ohm
Where is the problem ?
if ohms law applies I=U/R = 2.4/ 5.51846E-3 = 435A for an area of 70cm2 ie, current density 6.2 A/cm2
Where am I making mistake?
Resistivity of steel 316L for 60C = 7,67232E-06 Ohm*mm
Specific electrical resistance 25% KOH for 60C = 9,657298288 Ohm*mm
Assume square electrodes 100x100mm, 30% of the area is for bubbles and free space for gas removal, i.e. the area of the electrodes is 7000mm2.
R electrodes = 2 * (7,67232E-06*0,3/7000) = 6,57627E-10 Ohm
R electrolyte= 9,657298288*2/7000= 2,759228E-03 Ohm
R cell= 5,51846E-03 Ohm
Where is the problem ?
if ohms law applies I=U/R = 2.4/ 5.51846E-3 = 435A for an area of 70cm2 ie, current density 6.2 A/cm2
Where am I making mistake?