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I read all topics about this issueHi,
did you see the many threads here in this forum about this topic?
I recommend to refine your question, especially:
* which formulas you refer to
* what especially confuses you
Klaus
This is not my graph. I cut them from other manuscriptsIn addition to impedance of its PN junction, the diode also contains a certain amount of ohmic resistance. As you push greater Amperes through the component, ohmic resistance accounts for ever greater percentage of its total impedance. Thus efficiency drops after you reach a certain current level. (11 dBm on your graph.)
Heating effect makes a difference in measurements. The longer time that the current is applied, the more temperature rises, and the diode's efficiency drops.
It's no surprise if simulations differ from real-life measurements.
Follow this example to simulate the "Vout vs. Pin" graph.I read all topics about this issue
But I can't find best formula for efficiency of rectifier.
How can I simulate these sample figures in ADS ? Vout and Efficiency?
Near. Suggest n = Vout^2 / (Rload x Pin)To plot this graph, you will need to write a measurement equation to calculate:
n = Vout x Rload / Pin