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Hello Marat86
As you have seen the feed location and system are presented in the image. so what are you asking precisely, because the question is quite ambiguous.
Regards
Elchiquito
checchangfu
There is a minimum distance that needs to be maintained between elements if you want to avoid grating lobes and this distance is dependent on the scan angle of the arrays.
generally speaking its always good to stick to less than half a lambda distance between elements.
Hope that...
ABU MARIA
Coupling is mainly due to different conductors sharing same plane for return. one way of decreasing the coupling between elements is to use non conventional feeding methods such as aperture coupled methods.
i am not very familiar with ADS and its capabilities , HFSS will surely do...
Vishal
I will check your file and let you know. what is the error or message of adpative passes, that they didnt converge or did they converge?
Regards
Elchiquito
Hello Vishal
from the paper you can see the dimensions of the triangular to be truncated. Draw a triangle using the lines and then use the Boolean function and subtract it from the trace .
Hope that helps
Regards
Elchiquito
The only Reason i can think of is that you are continuing with the same line width as of 50 ohms. since power is getting divided more in like a parallel circuit the width of the line should be 100 ohms. (100*100)/200=50 ohms, where you will get better reflection coefficient. let me know if it...
Hello GiedriusR
As far as the feed network is concerned, there is nothing wrong with the network unless, network has not been built properly. if you have mismatches in one section it builds up through out the system and leads to a poor reflection coefficients. on top of it your feed network...
Albbg
theta=-.0859(rad) refers to the same angle as 3.056(rad) depends how you measure the angle? 3.056+.0859 is Pi radians.
which still doesn't solve the problem, reason for the post. like me and enjunear has mentioned probably a mistake or a typo
Regards
Elchiquito
Ashish
here we go. our example here is a patch, E-field is in the direction of the field lines, so theta=90 for variable phi is E plane, H-plane is phi=0 and theta=0 to 180. and the polarization of the patch antenna here is horizontal polarization, right? since the polarization is the trace of...
hello
-0.3530 + 0.0304i which can also be written in this form mag*exp(j*theta)
here magnitude will be .355 theta =3.0557 which by any logic cant be rounded off to 1. i strongly believe there might have been misunderstanding or a typo.
hope that helps
Regards
Elchiquito
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