Wilkinson Divider Current Density

[ge]

If I simulate a Wilkinson Power Divider current density without the isolation resistors, will I get current density minimums at the locations where the isolation resistors belong? I'm running AWR/Microwave Office.

Tnx,
GE

 

[volker@muehlhaus]

Where is your feed? If you feed from the common port, the structure is symmetric and there is no current through the resistor anyway.

 

[ge]

The feed could be from either direction depending on how the divider/combiner is used. If I feed from the divider ports (not common port), I guess that I will need to excite both divider ports in-phase.

 

[volker@muehlhaus]

The feed could be from either direction depending on how the divider/combiner is used. If I feed from the divider ports (not common port), I guess that I will need to excite both divider ports in-phase.

Yes, the resistor is only needed for isolation (asymmetric currents).

 

[electron27]

Yes, the resistor is only needed for isolation (asymmetric currents).

Yes, the resistor is only needed for isolation (asymmetric currents)[/I][/B].....
Not only, The resistor is also needed to provide the matching to Z0 system of the output ports.