ZengLei
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the voltage between C1 is U AND the value of C1=C2=C
When the switch J1 is open the Energy of the system is E1=1/2C*U*U
When the switch J1 is closed,the voltage through the 2 paralelled capacitors C1 and C2 is 1/2U
so the energy of the system is E2=0.5*(0.5U)*(0.5U)*(2C)=0.5E1
so the question is where is the energy gone????
what does it changes into???
Thanks
When the switch J1 is open the Energy of the system is E1=1/2C*U*U
When the switch J1 is closed,the voltage through the 2 paralelled capacitors C1 and C2 is 1/2U
so the energy of the system is E2=0.5*(0.5U)*(0.5U)*(2C)=0.5E1
so the question is where is the energy gone????
what does it changes into???
Thanks