Where to connect VCAP/VDDCORE pin on PIC24FJ64GA004?

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treez

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Hello,

I am using PIC24FJ64GA004 and i am not using the on-chip regulator. (i've disabled it)

-So do you know to what i should connect the VCAP/VDDCORE pin?

Page 21 of the datasheet says ..................


When the regulator is disabled, the VCAP/VDDCORE pin
must be tied to a voltage supply at the VDDCORE level.
Refer to Section 27.0 “Electrical Characteristics” for
information on VDD and VDDCORE.


However, section 27 doesnt tell how to connect this pin when the regulator is disabled.

PIC24FJ64GA004 DATASHEET:
**broken link removed**
 

I am using PIC24FJ64GA004 and i am not using the on-chip regulator. (i've disabled it)

-So do you know to what i should connect the VCAP/VDDCORE pin?

However, section 27 doesnt tell how to connect this pin when the regulator is disabled.

You answer lies in the quote from the device datasheet:

When the regulator is disabled, the VCAP/VDDCORE pin
must be tied to a voltage supply at the VDDCORE level.

Refer to Section 27.0 “Electrical Characteristics” for
information on VDD and VDDCORE.

If you disable the internal regulator, you must connect the VCAP/VDDCORE pin to a voltage supply at proper VDDCORE level.

The proper voltage range for VDDCORE is 2.0V to 2.75V, note a voltage below 2.35V will steadly decrease the maximum clock frequency of the device until 2.0V is reached at which point the devices maximum clock frequency is 16MHz.

A proper supply of VDD is still required, which can range from VDDCORE to 3.6V.





Reference: PIC24FJ64GA004 Family Datasheet, Section: 24.2 On-Chip Voltage Regulator, Page: 213




I'm curious as to why you feel disabling the internal regulator is necessary?

The device has an operational voltage range of 2.0V to 3.6V, without disabling the internal regulator.

BigDog
 
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i need to disable the internel regulator becasue its only 2 to 2.75V......and some of the voltages presenting at the PIC pins will be greater than that......up to 3.6V.......so i must power the PIC from 3.6V too.

Or have i got this wrong, is the 2 to 2.75V just an internal voltage that i can enable and forget about, and happily put voltages up to 3V6 on any pin?
 

Yes, you are wrong. The internal working voltage of the CPU is totally transparent to the user. Your I/O voltage will be whatever you use for VDD (and you can still use 5V I/O provided you set up the ports correctly on the 5V tolerant ones).

Keith.
 
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The internal voltage regulator is used to drop VDD to 2.5V to power the core digital logic of the PIC24F at 2.5V. If you disable the internal voltage regulator, VDD must be about 2.5V. When you use 3.3V VDD, the internal voltage regulator must be enabled and you must connect the capacitor from VCAP to ground. The IO pins will be roughly equal to VDD when high, as the internal voltage regulator affects only the PIC24F core, but not the IO lines.



Hope this helps.
Tahmid.
 

If you disable the internal voltage regulator, VDD must be about 2.5V. When you use 3.3V VDD, the internal voltage regulator must be enabled and you must connect the capacitor from VCAP to ground.

Actually, your statement is incorrect.

If the internal voltage regulator is disable, the only requirement of VDD is the supplied voltage must be within the VDDCORE to 3.6V range, which includes the 3.3V level discussed.

VDDCORE can certainly by supplied by another voltage source as long as the supplied voltage remains within the 2.0V to 2.75V range.

Reference the middle configuration, internal voltage regulator disable, VDD supplied at 3.3V and VDDCORE supplied at 2.5V.




BigDog
 
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    Tahmid

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