The simplest squarer circuit is actually a MOSFET because the output current is proportional to the square of VGS in the saturation region. Actually, it is usually a current mode working. For independance of VDS, you ofcourse can cascode the Common source amplifier.
Ya~ Just a MOS . That's a good idea. Thanks!
But, has any other circuit with square function ?
I provide one as listed below. Iout=Iin²/4Iα (ref:Analog IC design:the current-mode approach , C.Toumazou ,1990)
I understand the concept of the square law i=f(vgs^2) but
can anyone explain me how you can produce a current squarer based on this law?
I am reffering specifically on pages 16-17 of the below book http://www.ifi.uio.no/in241/Gruppe/avlsi.pdf
("Why, Where and How? Eric A.Vittoz CSEM")