Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Register Log in

wavelength in MMIC, do you know ? how to define

Status
Not open for further replies.
S

shanmei

Advanced Member level 1
Joined
Jul 26, 2006
Messages
430
Helped
8
Reputation
16
Reaction score
8
Trophy points
1,298
Location
USA
Activity points
4,496
How does he get the wavelength 82um*4=328um, which for 60GHz?

the wavelength would be c/f=(3*10^8)/(60*10^9)=5mm.

5mm is not equal to 328um.
1.png
 

Wavelength is also function of substrate so that is
lambda(eff)=lambda(0)/sqrt(Er(eff))
The wavelength which you found is valid for space but in the substrate it will be different in according with that relation.
 
BigBoss said:
Wavelength is also function of substrate so that is
lambda(eff)=lambda(0)/sqrt(Er(eff))
The wavelength which you found is valid for space but in the substrate it will be different in according with that relation.
Click to expand...


Thanks.Thanks.
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top