Swend
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Really? I would expect constant energy per pulse.The average power remains the same regardless of pulse length
Really? I would expect constant energy per pulse.
I presume most readers can understand the problem better if you show a circuit of the existing system from which the pulse energy shall be absorbed/recovered.
Here's the pulse given, measured over a restive load.
Voltage and current do not appear to be in phase.
You can multiply current and voltage point by point and plot on the same graph.
The applied pulse is not clearly seen. Also the phase difference does not stay constant.
Have you a decent power factor corrector in place? That can save some power on the long run.
Or, am I getting everything wrong? You are applying a rectangular pulse to a resistive load and seeing these ringing?
Yes, that is what I did to calculate average power. And I used the absolute values because it is a resistive load.
Using absolute values to calculate power is not correct.
Your case appears to have considerable source reactance. Hence any correction need to be made to the source side.
Power factor correction need to be done based on the load power and the approx frequency (of the pulse); As your load is resistive, some capacitor added to the source side can make considerable improvement.
If it is the result from a single pulse, you need to take care of the source impedance. That is my best guess.
p.s. I can see they are clearly in phase - with a rising DC offset near the end - which makes it look as if they aren't.
extending the time of the pulse is useful as it allows a wider range of power components to be used - if you advise the peak volts and current over the 300uS you mention I can supply a few suggestions.
Why did you mention an air cored Tx? do you need to isolate the output recovered energy?
p.s. I can see they are clearly in phase - with a rising DC offset near the end - which makes it look as if they aren't.
How about the idea of attaching diodes and capacitors, to convert the waveforms into a DC supply?
if you advise the peak volts and current over the 300uS you mention I can supply a few suggestions.
as to in phase - I meant rather in synchronism, as in
constant phase difference,
so 45kV peak and 6500 Apk ... ?
I have learned that in a resistive load, the negative power is also power dissipated in the load....
Positive power is consumed and negative power is produced.
If you have learnt that negative power is dissipated, you are wrong.
In this particular case, you need to multiply point by point the voltage and current to get the overall power used in the load and finally appears as dissipation. You should do the summation over at least one complete period..
Which I did, over the whole 140 uS - and the result is 340KW.
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