VEBO parameters in transistors

[rover]

I know that the VEBO is the emmitter to base voltage limit on transistor specifications, but is this the reverse breakdown limit on a bjt? i do not understand why this is stated. Since the potential between the base and the emmitter will be 0.6V.
Does anyone have the answer?
Does anyone know where i can get help explaining the transistor datasheets and what each parameter is for?

THANkX

ROVER

 

[papyaki]

vebo bjt

Hi,

Vebo is the emitter to base voltage. It is the max reverse voltage (or breakdown voltage), typicaly comprised between 3v and 5v. As i was student, it was also named "reverse Vbe".

Vbeo is the direct base to emitter voltage, typicaly comprised between 0.6v and 0.7v. Note than Vbeo max is about 1.2v

 

[flatulent]

vebo 2v

One further item is the o at the end means that the remaining terminal (collector in this case) is left floating (open).

 

[BigBoss]

bjt vebo คือ

VBEO ( Base Emitter Open Collector Breakdown Voltage ) is a limit for every bipolar transistor. It can be up to 2V and beyond this limit , B-E junction of the transistor may be broken.
It depends on semicondictor technology and doping concentration in junctions.
Rgrds