tempos
Member level 2
About using an old mobile phone as an universal Li-Ion battery charger
I have an old Siemens mobile phone that uses a 700 mAh, 3.7V battery like this:
https://www.amazon.co.uk/Li-Ion-battery-suitable-Siemens-Gigaset/dp/B00BU24ETU (see also the attached picture)
I also have an unused new 670 mAh, 3.7V Digipower BP-70A digital camera battery.
See: https://www.digipowersolutions.com/product/88/battery-replacement-samsung-bp70a-bp-70a.html
Both Li-Ion batteries have 3 contacts: plus, minus and a third one in the middle. Unfortunately the contacts are located in different positions and I can not simply fit inside the Siemens phone the BP-70A battery and see if it is charged. I need to run wires from the plus, minus and the third contact of the BP-70A battery to the corresponding pins of my phone.
The question is, will the Siemens phone charge the BP-70A battery, stop in time when it reaches full capacity and latter the same phone be able to use this battery as if it is its own original power supply or this arrangement (trick) will not work?
I have an old Siemens mobile phone that uses a 700 mAh, 3.7V battery like this:
https://www.amazon.co.uk/Li-Ion-battery-suitable-Siemens-Gigaset/dp/B00BU24ETU (see also the attached picture)
I also have an unused new 670 mAh, 3.7V Digipower BP-70A digital camera battery.
See: https://www.digipowersolutions.com/product/88/battery-replacement-samsung-bp70a-bp-70a.html
Both Li-Ion batteries have 3 contacts: plus, minus and a third one in the middle. Unfortunately the contacts are located in different positions and I can not simply fit inside the Siemens phone the BP-70A battery and see if it is charged. I need to run wires from the plus, minus and the third contact of the BP-70A battery to the corresponding pins of my phone.
The question is, will the Siemens phone charge the BP-70A battery, stop in time when it reaches full capacity and latter the same phone be able to use this battery as if it is its own original power supply or this arrangement (trick) will not work?