David Levy
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I want to better understand the nature of the increase in npn collector current with increasing temperature.
For Vbe held constant we know that this current approximately doubles with every 10 degree C increase in temperature. I believe there are two sources of this current increase and that they add to each other (they are in the same direction, and they do not partly cancel each other). Both depend on the temperature dependence of Is. The first is that more base-emitter current will flow. This is just an increased forward biasing of the base-emitter junction with temperature (Vbe held constant). This is normal transistor action. In the equation for Ic, Is increases with temp, and so Ic increases with temp. The second source of current is due to EHP generation across the reverse biased collector base junction. In this case, the appropriate equation is the diode equation under reverse bias. In this case Is is still increasing with temperature. Here we can think of the increase in current as coming from an increase in thermally generated electron-hole pairs (EHPs) in the depletion region. Now for the key point: at the reverse biased collector base junction, the thermally generated holes will follow the depletion region electric field and will flow into the neutral base. This flow of holes back into the base and of electrons back into the collector is what we would normally call reverse current or leakage current in a diode. In this case, what do the holes do when they move into the neutral base? Do they stimulate more emitter current? Is this process similar to the beta multiplication that we see in Vceo breakdown? What is the magnitude of this leakage current compared to first current component described above (the further forward biasing of the base-emitter junction)? If it is insignificant, then the whole description of "leakage current" as describing what happens to an npn with increased temperature is confusing, because strictly speaking, "leakage current" is in the direction of reverse (diode) current. So, finally, is the doubling of Ic with temp mainly due to the enhanced base-emitter conduction, and what role does the collector-base leakage current play in this doubling of Ic with temp?
For Vbe held constant we know that this current approximately doubles with every 10 degree C increase in temperature. I believe there are two sources of this current increase and that they add to each other (they are in the same direction, and they do not partly cancel each other). Both depend on the temperature dependence of Is. The first is that more base-emitter current will flow. This is just an increased forward biasing of the base-emitter junction with temperature (Vbe held constant). This is normal transistor action. In the equation for Ic, Is increases with temp, and so Ic increases with temp. The second source of current is due to EHP generation across the reverse biased collector base junction. In this case, the appropriate equation is the diode equation under reverse bias. In this case Is is still increasing with temperature. Here we can think of the increase in current as coming from an increase in thermally generated electron-hole pairs (EHPs) in the depletion region. Now for the key point: at the reverse biased collector base junction, the thermally generated holes will follow the depletion region electric field and will flow into the neutral base. This flow of holes back into the base and of electrons back into the collector is what we would normally call reverse current or leakage current in a diode. In this case, what do the holes do when they move into the neutral base? Do they stimulate more emitter current? Is this process similar to the beta multiplication that we see in Vceo breakdown? What is the magnitude of this leakage current compared to first current component described above (the further forward biasing of the base-emitter junction)? If it is insignificant, then the whole description of "leakage current" as describing what happens to an npn with increased temperature is confusing, because strictly speaking, "leakage current" is in the direction of reverse (diode) current. So, finally, is the doubling of Ic with temp mainly due to the enhanced base-emitter conduction, and what role does the collector-base leakage current play in this doubling of Ic with temp?