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TV cable signal splitter...

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Externet

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Hello.
Borrowed images from the web; should work for asking.

1629047581241.png
1629047623653.png



If two inductors are added to the circuit above, connected each jumping from 'input' to each 'output' Would it become a "DC pass" kind of splitter as the one below, or something else should be considered ? ( Did not find a generic schematic sample for the DC pass flavor )

1629047833257.png
 

Assuming that the DC current to be passed is low and and will have no or minimal effect on the transformers, move the input capacitor to the grounded end of T1 and remove C3 & C4, there will then be a DC path from the input to both outputs.
The input capacitor should be large enough so that its impedance at the lowest operating frequency has minimal effect on the input impedance.
 

The circuit looked odd to me, it looks like it has been copied from a patent application. I assumed that L1 - L4 were representing the connecting wires, and that it is supposed to be DC isolated on all ports, hence the capacitors.
I cant see much use for C1 & C2., but then Externet did imply that it was just an example circuit.
 

That's what I would expect, too. The solution in post #2 (insert a capacitor at T1 footpoint) should work. Probably want to connect multiple ceramic capacitors in parallel for low inductance.
 

Thanks, gentlemen.
At first, the schematic linked at post #5 seemed a DC pass device but it is not, T1 being few turns on ferrite. Will have to modify one as suggested.
 

Take care that the DC current does not saturate the transformer ferrites
 

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