don't understand what you mean, R1 should be 470Ohm? I tried this and not working. what do you mean by 2k0 base to RHS(Right Hand Side) of C?you need a resistor above R, 2k0 base to RHS of C, and Ritself should be 470 ohm, then collector goes straight up to RHS of C - this will give you a 2v5 clamp ...
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you can scale these values also, e.g. 4k7 & 20k
do you mean like this?I'm sorry if you can't under stand simple instructions, there must be 2 resistors, the extant one shown must be 470 ohm, and the other needed one is from the base to the collector, i.e. the RHS of the cap, AND the collector must connect to the RHS of the cap too ....
I got the circuit drawing from here:https://www.nutsvolts.com/magazine/article/bipolar_transistor_cookbook_part_1I understand the problem differently.
You want to clamp negative voltage but post #1 circuit clamps positive voltage. Wrong transistor polarity.
After flipping the polarity you'll get -0.7/4.3 V pulse. If you want ideal 0/5V output, a more complex circuit is required.
I guess there is a misunderstanding. I did not mean to use CB diode.Transistor as diode is neither weaker or stronger than regular diode, I think. CB diode has higher breakdown voltage than EB, in so far preferred.
so you did not read my 1st post? I'm sorry if you cannot understand simple diagram that has been posted, let alone the problem described in words.and for clamping both ways for a bi-polar input ( & output signal )
View attachment 179414
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@FvM - I see your point - re-reading post #1 it appears he/she wants a -2v5 to 2v5 amplifier to 0 - 5V
i.e. -2v5 in = 0v out and +2v5 in = 5V out .... a buffer / amplifier not so much a clamp ...
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Yes - in fact "clamp" is a bt of a misnomer for " DC restorer " circuit as follows:
View attachment 179415
so +/- 2v5 turns into 0 - 5V, best to use a low Vf schottky, and make sure the source can supply the required currents ....
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the R can be 1Meg or larger to give a decent time constant ....
I understand the problem differently.
You want to clamp negative voltage but post #1 circuit clamps positive voltage. Wrong transistor polarity.
After flipping the polarity you'll get -0.7/4.3 V pulse. If you want ideal 0/5V output, a more complex circuit is required.
Transistor as diode is neither weaker or stronger than regular diode, I think. CB diode has higher breakdown voltage than EB, in so far preferred. The problem with Fig.7 schematics in the link is however that both have wrong polarity.
what additional circuit is required if I wanted 0/5V output? this is just interesting to me...I understand the problem differently.
You want to clamp negative voltage but post #1 circuit clamps positive voltage. Wrong transistor polarity.
After flipping the polarity you'll get -0.7/4.3 V pulse. If you want ideal 0/5V output, a more complex circuit is required.
My - hopefully - objective point of view.so you did not read my 1st post? I'm sorry if you cannot undgerstand simple diagram that has been posted, let alone the problem described in words.
Indeed it's a negative clamper. It limits the negative voltage to about -600mV.(hinted by the Positive Clamper
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