yes,lt spice files
actually i made a circuit sumthing like this but i had a power breakdown and file gets deleted
so i am in really bad situation right now
After I wrote you a reply, edaboard deleted it before I had the chance to copy it while writing.
So here I am again.
It seems you expect me keep working on your homework... but we didn’t agree first on the salary. :smile:
I believe you are an intelligent student but you like to skip some steps with the hope to speed up your work.
But I hope you don't really believe that some of your classmates have a more powerful brain than yours... or have more time than you do?
In any case, it is not wrong to ask for help, in fact one needs a real courage to do it and say “Help me”.
On the other hand, helping is usually much easier (and as you know, it could give the helper the feeling of superiority :twisted: ).
I will try to complete the circuit for you. But please remember, it isn’t meant a solution for a real project.
In courses, problems are given to clarify one (or more) points like theorems or method of analysis... etc.
So the idea of our solution is more important than the circuit itself. It is about a method of increasing S/N at the amplifier output.
Personally I try to figure out how we let the comparison of the S/N be meaningful in our problem. If we let B=1 then the amplifier gain will be close to 1. But without the idea of feedback (that is adding the noiseless G1 and B) the amplifier gain is G2=50. I mean we were comparing two amplifiers having different gains. If I am not wrong we need to let the gain of the new amplifier (with feedback) equal to the original gain G2, though this won’t change the S/N since it depens on G1 only (I wonder what is in the mind of your lecturer).
Without feedback
Vo/Vs = G2
With feedback
Vo/Vs = (G1*G2)/(1 + B*G1*G2)
Therefore
(G1*G2)/(1 + B*G1*G2) = G2
G1/(1 + B*G1*G2) = 1
1 + B*G1*G2 =G1
B = (G1 – 1)/(G1*G2)
B= (56.23-1)/(56.23*50)
B=1/50.9 (it is almost as 1/G2)
What do you think?