[SOLVED] Some problem understanding the code

[saur]

#define SDRAM_BASE_ADDR 0x28000000

static uint16_t *fb  = (uint16_t *)SDRAM_BASE_ADDR;

void GLCD_DrawChar (unsigned int x, unsigned int y, unsigned int cw, unsigned int ch, unsigned char *c) {
  unsigned int i, j, k, pixs;

  k  = (cw + 7)/8;

  if (k == 1) {
    for (j = 0; j < ch; j++) {
      pixs = *(unsigned char *)c;
      c += 1;
    
      for (i = 0; i < cw; i++) {
       #if (LANDSCAPE == 0)
        fb[(y+j)*PHYS_XSZ + (x+i)] = Color[(pixs >> i) & 1];
       #else
        fb[(x+i)*PHYS_XSZ + (y+j)] = Color[(pixs >> i) & 1];
       #endif
      }
    }
  }
  else if (k == 2) {
    for (j = 0; j < ch; j++) {
      pixs = *(unsigned short *)c;
      c += 2;
      
      for (i = 0; i < cw; i++) {
       #if (LANDSCAPE == 0)
        fb[(y+j)*PHYS_XSZ + (x+i)] = Color[(pixs >> i) & 1];
       #else
        fb[(x+i)*PHYS_XSZ + (y+j)] = Color[(pixs >> i) & 1];
       #endif
      }
    }
  }
}

In the above code the only problem I'm facing is that, fb has been defined as a pointer. Then what does the code

 fb[(y+j)*PHYS_XSZ+(x+i)]

mean?

Here PHYS_XSZ has been defined as 240. I also understand what

Color[(pixs>>i)&1]

means.

Just help mw with the fb part of the code.

Thanks

 

[Venkadesh_M]

A pointer can be addressed in different ways

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Code C - [expand]
1
2
*( fb + i )
    fb[ i ] //are same

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[forforum]

This code used to display a character at the position x,y.
LCD has matrix COLxROW RAM to store character (all characters are display on LCD).
So function will saved the character to RAM of LCD at position x,y.
PHYS_XSZ is number of characters on a line.