sir help me rhis 16f72 c code

[sitaram]

unsigned char adc_read(unsigned char chanel)
{

chanel<<=3;
ADCON0=0xc1|chanel;
sir i not understand it

 

[jayanth.devarayanadurga]

If chanel = 1 then it is shifted 3 bits left so it becomes 0x08 after executing

---

Code C - [expand]
1
chanel<<=3;

---

ADCON is assigned the value got by ORing 0xC1 and chanel value.

If chanel was 0x08 then 0xC1 ORed with 0x08 will be assigned to ADCON0 regsiter.

 

[betwixt]

or even the ADCON0 channel :-D
Jayanth is right though, it uses the value in 'chanel' to set the bits in ADCON0 by ORing them with 0xC1. The value you provide is shifted three places to the left so it aligns with the channel bit positions in the register.

Brian.

 

[paulfjujo]

hello

chanel=chanel << 3;  // chanel value transmitted by the paramter of unction is multiply by 2 power 3 = 8 
ADCON0= 0xC1 | chanel;      // OR function to add the chanel number into the register

so chanel 0 will give 0xC1
chanel 1 -> 0xC9
chanel 2 -> 0xD1
chanel 3 -> 0xD9
.....

 

[betwixt]

That's correct - you understood it!

Brian.