I made my first circuit the other day.
Congratulations! You want to make lots of noise? You can add a power driver to each of the channels and get a bigger power supply and bigger speakers.
You can make Simple Audio Amplifier Circuit for mobile or laptop using Single Mosfet or Single transistor . circuit diagram of very simple and Powerful Audio Amplifier For Listen the Audio from any Mobile or Laptop. The construction of this small Audio Amplifier is very Easy and this is very simple. Use heat sink with Mosfet. This circuit Works Well with 6-9 v supply.
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For More amplifier circuit
Congratulations! You want to make lots of noise? You can add a power driver to each of the channels and get a bigger power supply and bigger speakers.
Hi,
Power means voltage and current.
Voltage without current is no power...current without voktage is no power, too.
A speaker has a nominal impedance - it will vary with frequency - but you can calculate with it.
Example:
Let's say you have a speaker with 4Ohms...and the amplifier is able to drive 12V peak output.
If the amplifier can drive 100mA only ... then the peak power is limited to I × I × R ... which is 40mW peak only.
Due to current limitation the output voltage will be limited to I × R = 400mV peak.
According Ohm's law a load with 4Ohms will draw 3A from 12V.
Thus this amplifier needs to be able to drive 3A...then you get a peak power of 36W.
But if the same amplifier is able to drive 10A, then the peak output power won't increase, because it is limited by the 12V voltage.
In short: For a high power amplifier you need high voltage as well as high current.
Klaus
An amplifier powered from 12V will have a peak output of about 3W into 4 ohms (TDA2009). Its peak output is about 4.9V, not 12V, because its output idles at half the supply voltage which is 6V and its output has a voltage loss of about 2.2V peak to peak.Example:
Let's say you have a speaker with 4 Ohms...and the amplifier is able to drive 12V peak output.
No. The peak voltage in 4 ohms with a 12V supply is only 4.9V then Ohm's Law calculates the peak output current to be 4.9V/4 ohms= 1.23A.According Ohm's law a load with 4 Ohms will draw 3A from 12V.
Thus this amplifier needs to be able to drive 3A...then you get a peak power of 36W.
I need a simple circuit to build an unregulated power supply around 16VDC +/-
There is no such thing as peak power, it is simply the real sinewave power doubled,
While I clearly talk about output voltage you talk about supply voltage.Example:
Let's say you have a speaker with 4 Ohms...and the amplifier is able to drive 12V peak output.
Many cheap amplifiers are advertised saying "peak" power or "maximum" power which simply doubles the real sinewave power. The real sinewave power has a sinewave at the output with the RMS voltage level as high as it can go without clipping. Peak power is simply double that since the voltage peak is 1.414 times (the root of 2) higher and then the current is also the root of 2 times higher. 1.414 x 1.414=2.Can you please explain this in simple English? This sounds Greek or Hebrew (no offence intended) to me. I understand each word individually but I cannot get what is the intended meaning...
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