ring oscillator problem

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fanshuo

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ring oscillator + spice simulation setup

hi

I built a linear model of ring oscillator in LT spice,as shown in the figure
I set the initial condition to be 1V
and I found the output to be oscillated with amplitude of 3.5V
if I double the initial condition to be 2V
then the corresponding output amplitude is changed to 7 V

Is there anybody can explain why the amplitude is 3.5V to me?


Thanks
 

what is the supply voltage. the oscillator should oscillate from vdd to vdd-ir, where r is the resistance of the load of the delay element.i is the current when full switching occurs .

amarnath
 

amarnath said:
what is the supply voltage. the oscillator should oscillate from vdd to vdd-ir, where r is the resistance of the load of the delay element.i is the current when full switching occurs .

amarnath
Click to expand...


This is just a linear model of ring oscillator
It will never saturate
 



hi
i think you can calculte the amplitude of the oscillation by energy conservation roughly.
jeff
 
jfyan said:
hi
i think you can calculte the amplitude of the oscillation by energy conservation roughly.
jeff
Click to expand...

I tried
but not sucessful
 


besides, i think, the oscillator you bulit can not keep in its stable oscillation, because it is linear model. as i know, only non-linearity can limit the oscillation
amplitude. so if the oscilation set up stablly, non-linearity must exist in your system. correct me if above is wrong.
jeff
 



Yes, in normal ring oscillator it should start with a transfer gain>1
in my case it is set to be exact 1
so no saturation will happen
and it is also stable

the stable oscillation amplitude should determined by the initial condition
but I have not figure out how exactly it is

regards,
 

linear model is not accurate, run tran simulation
 


hi

yes, i now understand your question.
it is a critical ponit when you set the gain of each stage is 2.
actually, we can set up three equations to solve this network in s-domain, right?
and then convert the v1(s),v2(s),v3(s) into time domain with initial state, remember, v1(0)=1,v2(0)=-2, and v3(0)=4.
i think, the spice simulation just did the same thing.

jeff
 

and I found the output to be oscillated with amplitude of 3.5V
if I double the initial condition to be 2V
then the corresponding output amplitude is changed to 7 V

Is there anybody can explain why the amplitude is 3.5V to me?
Click to expand...

In every oscillator should be non linearity to determine the amplitude of the oscillation. Otherwise, it depends on the initial conditions. Therefore you may need to add a limiter to your linear circuit or there is another way:

You can use ALC : Automatic Level Controller.
In this manner you will have another feedback to determine the amplitude of oscillation.
 

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