kae_jolie
Full Member level 4
what is the relationship between gain and electric field?
My answer is:
radiation intensity (U) = ½ Re(E x H*) • r²
Directivity (D) = U/Uave
Gain (G) = e D
Therefore, G = e (U/Uave) = e [(½ Re(E x H*) • r²)/(Uave)]
Therefore, electric field (E) is directly proportional to Gain (G), so as E increases Gain will increase and vice versa.
Is this a correct statement? If not, please explain.
Thanks.
My answer is:
radiation intensity (U) = ½ Re(E x H*) • r²
Directivity (D) = U/Uave
Gain (G) = e D
Therefore, G = e (U/Uave) = e [(½ Re(E x H*) • r²)/(Uave)]
Therefore, electric field (E) is directly proportional to Gain (G), so as E increases Gain will increase and vice versa.
Is this a correct statement? If not, please explain.
Thanks.